按名称和最大类别从数组中删除重复对象

Question

我应该如何删除符合条件的重复对象？假设我有这个数组：let my_array = [  { name: "foo", version: "10" },  { name: "foo", version: "60" },  { name: "foo", version: "20" },  { name: "bar", version: "400" },];我需要避免重复包含最新版本的对象。我知道我可以使用 Set 来删除重复项：let unique = my_array.filter((set => f =>    !set.has(f.name) && set.add(f.name)  )  (new Set))最大版本条件下的预期结果是：let my_array = [  { name: "foo", version: "60" },  { name: "bar", version: "400" },];

Answer 1

使用object.Values和reduce来删除重复项并获取version每个的最大值name。

演示

let my_array = [

  { name: "foo", version: "10" },

  { name: "foo", version: "60" },

  { name: "foo", version: "20" },

  { name: "bar", version: "400" },

];

let unique = Object.values(my_array.reduce((r, x) => {

  r[x.name] = r[x.name] && r[x.name].version > x.version ? r[x.name] : x

  return r

}, {}))

console.log(unique )

Answer 2

您可以通过使用来实现结果reduce

let my_array = [{

    name: "foo",

    version: "10"

  },

  {

    name: "foo",

    version: "60"

  },

  {

    name: "foo",

    version: "20"

  },

  {

    name: "bar",

    version: "400"

  },

];

var new_array = my_array.reduce((max, b) => Math.max(max, b.version), my_array[0].version);

console.log(new_array)