3 回答
TA贡献1825条经验 获得超6个赞
使用map和听写理解:
dct = {"a": [100, 200, 300], "b": [-100, 200, 100]}
def changer(number):
char = "D" if number > 100 else "DI"
return f"{char}{number}"
new_dct = {key: list(map(changer, values)) for key, values in dct.items()}
print(new_dct)
输出
{'a': ['DI100', 'D200', 'D300'], 'b': ['DI-100', 'D200', 'DI100']}
TA贡献1815条经验 获得超13个赞
def dict_change(dicto):
modified_dict = {}
for key,value in dicto.items():
key_tuple = tuple((('D' if no>100 else 'DI')+ str(no) for no in key))
modified_dict[key_tuple] = value
return modified_dict
old_dict = {(110, 12, 13, 14, 15, 101): 'ba', (12, 126, -127, 128): 'pa'}
print(dict_change(old_dict))
输出
{('D110', 'DI12', 'DI13', 'DI14', 'DI15', 'D101'): 'ba', ('DI12', 'D126', 'DI-127', 'D128'): 'pa'}
TA贡献1877条经验 获得超1个赞
这是最紧凑的单行方式:
src = {(11, 12, 13, 14, 15, 16): 'ba', (125, 126, 127, 128): 'pa'}
d_out = {tuple(['Di','D'][i>100]+ str(i) for i in k):v for k,v in src.items()}
print(d_out)
Out[1]:
{('Di11', 'Di12', 'Di13', 'Di14', 'Di15', 'Di16'): 'ba',
('D125', 'D126', 'D127', 'D128'): 'pa'}
说清楚
在这种情况下,如果i less than or equal 100给 ['DI','D'][i>100]你['DI','D'][False]解释为['DI','D'][0]并返回'DI'
在这种情况下,如果i great than 100给 ['DI','D'][i>100]你['DI','D'][True]解释为['DI','D'][1]并返回'D'
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