OSMNX 最短路径节点 - 获取节点行进时间

Question

我想使用 Osmnx 获取最短路径路线中节点之间的旅行时间。有没有办法获得节点之间的旅行时间。import networkx as nximport osmnx as oxox.config(use_cache=True, log_console=True)import pandas as pdpla__version__Piedmont, CA, USAG = ox.graph_from_place(place, network_type='drive')orig = list(G)[0]dest = list(G)[-1]route = nx.shortest_path(G, orig, dest)#fig, ax = ox.plot_graph_route(G, route, route_linewidth=6, node_size=0, bgcolor='k')for i, val in enumerate(route):    print(i, val, G.nodes[val]['x'], G.nodes[val]['y'])我想存储节点，在上面的循环中实现的纬度和经度，但是有没有办法存储两个节点之间的旅行时间和/或两个节点之间的距离。

Answer 1

OSM 关于速度和旅行时间的数据往往参差不齐。使用 OSMnx 的速度模块估算缺失的边缘速度并计算自由流动的行驶时间。

import networkx as nx

import osmnx as ox

import pandas as pd

ox.config(use_cache=True, log_console=True)

place = 'Piedmont, CA, USA'

G = ox.graph_from_place(place, network_type='drive')

# impute missing edge speeds and add travel times

G = ox.add_edge_speeds(G)

G = ox.add_edge_travel_times(G)

# calculate route minimizing some weight

orig, dest = list(G)[0], list(G)[-1]

route = nx.shortest_path(G, orig, dest, weight='travel_time')

# OPTION 1: see the travel time for the whole route

travel_time = nx.shortest_path_length(G, orig, dest, weight='travel_time')

print(round(travel_time))

# OPTION 2: loop through the edges in your route

# and print the length and travel time of each edge

for u, v in zip(route[:-1], route[1:]):

    length = round(G.edges[(u, v, 0)]['length'])

    travel_time = round(G.edges[(u, v, 0)]['travel_time'])

    print(u, v, length, travel_time, sep='\t')

# OPTION 3: use get_route_edge_attributes

cols = ['osmid', 'length', 'travel_time']

attrs = ox.utils_graph.get_route_edge_attributes(G, route)

print(pd.DataFrame(attrs)[cols])