自定义正文错误消息 - Spring boot REST

Question

我正在尝试自定义我的正文错误消息。我的springboot版本是2.1.5.RELEASE我要这个：{"This should be application specific"}但我收到这个：{    "timestamp": "2019-05-24T15:47:10.872+0000",    "status": 500,    "error": "Internal Server Error",    "message": "Not Found (404)",    "path": "/github/gifojhuinh4w5"}我的异常类是：@ControllerAdvicepublic class AppExceptionHandler extends ResponseEntityExceptionHandler {    @ExceptionHandler(Exception.class)    protected ResponseEntity<Object> handleConflict(Exception ex, WebRequest request) {        String bodyOfResponse = "This should be application specific";        return handleExceptionInternal(ex, bodyOfResponse,                new HttpHeaders(), HttpStatus.INTERNAL_SERVER_ERROR, request);    }}我的班级捕获异常@Controller@EnableAutoConfigurationpublic class GitHub {    @RequestMapping(value ="/github/{usuario}", produces = "application/json; charset=UTF-8")    @ResponseBody    public ResponseEntity<Object> quantidadeRepositorios(@PathVariable(value = "usuario")String usuario) throws IOException {        HashMap<String, Integer> map = new HashMap<>();        RepositoryService service = new RepositoryService();        GitHubClient client = new GitHubClient();        Gson gson = new Gson();        client.setOAuth2Token("key");        map.put("Total",service.getRepositories(usuario).size()); // exception captured here        return new ResponseEntity<>(gson.toJson(map), HttpStatus.OK);    }}

Answer 1

当 ExceptionHandler 捕获到异常时，构建一个响应实体并返回它，如下所示。

创建一个 ErrorResponseDTO 对象并为其设置消息。

public class ErrorResponseDTO {

    private String errorMessage;

}

在异常处理程序中，返回该 dto 对象。

    @ExceptionHandler(Exception.class)

    protected ResponseEntity<Object> handleConflict(Exception ex, WebRequest request) {

        ErrorResponseDTO errorDTO = new ErrorResponseDTO();

        errorDTO.setErrorMessage("This should be application specific");

        return new ResponseEntity<>(errorDTO, HttpStatus.INTERNAL_SERVER_ERROR);

    }

这将为您提供您正在寻找的有效载荷。

{

"This should be application specific"

}