2 回答
TA贡献1827条经验 获得超9个赞
要使相同的代码适用于多个重复的 HTML 结构,请按行为对每个元素使用相同的类。然后在某些事件发生时使用 DOM 遍历将元素彼此关联起来。
在您的情况下,您将使用closest()and next()to findtable与更改后的收音机相关的内容。另请注意,您应该使用checked无线电的属性以及change事件来确定所选的值。尝试这个:
$(document).ready(function() {
$('.form-check-inline input[type="radio"]').on('change', function() {
$(this).closest('.form-group').next('table').toggle(this.checked && this.value === 'Yes');
});
});
.show-dc-table {
display: none;
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<div class="form-group row">
<label class="col-sm-2 col-form-label">Do you have allergies?</label>
<div class="col-sm-10">
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="allergy" value="Yes">
<label class="form-check-label">Yes</label>
</div>
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="allergy" value="No">
<label class="form-check-label">No</label>
</div>
</div>
</div>
<table class="table table-striped show-dc-table">
<thead>
<tr>
<th scope="col">Alergic Reactions to</th>
<th scope="col">Yes</th>
<th scope="col">No</th>
<th scope="col">Notes</th>
</tr>
</thead>
<tbody>
<tr>
<td>Aspirin, Ibuprofen, Codeine</td>
<td><input type="radio" name="a1" /></td>
<td><input type="radio" name="a2" /></td>
<td><input type="text" /></td>
</tr>
</tbody>
</table>
<div class="form-group row">
<label class="col-sm-2 col-form-label">Do you have a cough?</label>
<div class="col-sm-10">
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="cough" value="Yes">
<label class="form-check-label">Yes</label>
</div>
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="cough" value="No">
<label class="form-check-label">No</label>
</div>
</div>
</div>
<table class="table table-striped show-dc-table">
<thead>
<tr>
<th scope="col">Alergic Reactions to</th>
<th scope="col">Yes</th>
<th scope="col">No</th>
<th scope="col">Notes</th>
</tr>
</thead>
<tbody>
<tr>
<td>Lorem ipsum</td>
<td><input type="radio" name="a1" /></td>
<td><input type="radio" name="a2" /></td>
<td><input type="text" /></td>
</tr>
</tbody>
</table>
TA贡献2016条经验 获得超9个赞
要概括任何 DOM 操作脚本,请不要使用硬编码 ID。使用closest, find, next,等方法prev。在此特定示例中使用了两种方法closest。find
$(document).ready(function() {
$('.form-check-inline input[type="radio"]').click(function() {
if ($(this).val() == 'Yes') {
$(this).closest('.form-group').next('table').show();
} else {
$(this).closest('.form-group').next('table').hide();
}
});
});
.table.table-striped {
display: none
}
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
<link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css"
integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">
<div class="form-group row">
<label class="col-sm-2 col-form-label">Do you have Allergies </label>
<div class="col-sm-10">
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="allergy" value="Yes" id="allergy-yes">
<label class="form-check-label">Yes</label>
</div>
<div class="form-check form-check-inline">
<input class="form-check-input" type="radio" name="allergy" value="No">
<label class="form-check-label">No</label>
</div>
</div>
</div>
<table class="table table-striped" id="show-dc-table">
<tr>
<th scope="col">Alergic Reactions to</th>
<th scope="col">Yes</th>
<th scope="col">No</th>
<th scope="col">Notes</th>
</tr>
</table>
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