如何在 javascript 的 setInterval 中运行异步函数

Question

如何setInterval在下面的示例中运行异步函数？ setInterval(async () => {                  }, millisPerHour);

Answer 1

尝试使用此代码

https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Statements/async_function

function resolveAfter2Seconds() {

      return new Promise(resolve => {

        setTimeout(() => {

          resolve('resolved');

        }, 2000);

      });

    }

    

    async function asyncCall() {

      console.log('calling');

      const result = await resolveAfter2Seconds();

      console.log(result);

      // expected output: "resolved"

    }

    

    asyncCall();`