从 C# 桌面应用程序中的 json 字符串响应中获取数据

Question

我有来自服务器的多个学生姓名的响应{"ENVELOPE":{"STUDENTLIST":{"STUDENT":["John","HHH"]}}}或单个学生姓名{"ENVELOPE":{"STUDENTLIST":{"STUDENT":"John"}}}如果有错误{"RESPONSE":{"LINEERROR":"Could not find Students"}}从这些回复中，如果没有错误，我想要学生姓名数组 else string with error ie string[] names = {"John","HHH"} or string[] names = {"John"} else string error = "Could not find学生”;我试过 JObject jObj = JObject.Parse(responseFromServer); var msgProperty = jObj.Property("ENVELOPE"); var respProperty = jObj.Property("RESPONSE"); //check if property exists if (msgProperty != null) {     var mag = msgProperty.Value;     Console.WriteLine("has Student : " + mag);     /*       need logic here :/ */ }                 else if (respProperty != null) {     Console.WriteLine("no Students"); } else {      Console.WriteLine("Error while getting students");                     }希望你得到这个..

Answer 1

通常我会建议在模型中反序列化你的对象，但由于该STUDENT属性有时是一个数组，有时是一个字符串，不幸的是，这很麻烦。我建议反序列化您收到的实际 xml，因为我希望 xml 模型更容易处理。

与此同时，这将起作用：

string input = "{\"ENVELOPE\":{\"STUDENTLIST\":{\"STUDENT\":[\"John\",\"HHH\"]}}}";

// string input = "{\"ENVELOPE\":{\"STUDENTLIST\":{\"STUDENT\":\"John\"}}}";

// string input = "{\"RESPONSE\":{\"LINEERROR\":\"Could not find Students\"}}";

JObject jObj = JObject.Parse(input);

if (jObj["RESPONSE"] != null)

{

    string error = jObj["RESPONSE"]["LINEERROR"].ToString();

    Console.WriteLine($"Error: {error}");

    // or throw an exception

    return;

}

var studentNames = new List<string>();

// If there is no error, there should be a student property.

var students = jObj["ENVELOPE"]["STUDENTLIST"]["STUDENT"];

if (students is JArray)

{

    // If the student property is an array, add all names to the list.

    var studentArray = students as JArray;

    studentNames.AddRange(studentArray.Select(s => s.ToString()));

}

else

{

    // If student property is a string, add that to the list.

    studentNames.Add(students.ToString());

}

foreach (var student in studentNames)

{

    // Doing something with the names.

    Console.WriteLine(student);

}