从 ARN 中提取资源 ID

Question

我在 AWS 文档中看到 ARN 格式是：arn:partition:service:region:account-id:resource-idarn:partition:service:region:account-id:resource-type/resource-idarn:partition:service:region:account-id:resource-type:resource-id我正在尝试resource-id从 ARN 获取。以下代码有效，但丑陋...我正在寻找如何改进它：func GetResourceNameFromARN(roleARN string) string {    if parsedARN, err := arn.Parse(roleARN); err == nil {        return parsedARN.Resource    }    return ""}func extractResourceId(arn string) string {    resource := GetResourceNameFromARN(arn)    switch len(strings.Split(resource, "/")) {    case 1:        switch len(strings.Split(resource, ":")) {        case 2:            return strings.Split(resource, ":")[1]        }    case 2:        return strings.Split(resource, "/")[1]    }    return resource}

Answer 1

我建议一个简单的正则表达式：

package main

import (

    "fmt"

    "regexp"

)

func main() {

    // Compile the expression once, usually at init time.

    // Use raw strings to avoid having to quote the backslashes.

    var validID = regexp.MustCompile(`[^:/]*$`)

    fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-id"))

    fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-type/resource-id"))

    fmt.Println(validID.FindString("arn:partition:service:region:account-id:resource-type:resource-id"))

}