如何将 JSON 响应包装在父对象中

Question

我的 Spring REST 服务的当前响应如下：[    {        "id": "5cc81d256aaed62f8e6462f4",        "email": "[e-mail]"    },    {        "id": "5cc81d386aaed62f8e6462f5",        "email": "[e-mail]"    }]我想将它包装在一个 json 对象中，如下所示： {   "elements":[      {        "id": "5cc81d256aaed62f8e6462f4",        "email": "[e-mail]"    },    {        "id": "5cc81d386aaed62f8e6462f5",        "email": "[e-mail]"     }  ]} 控制器：   @RequestMapping(value = "/users", method = GET,produces = "application/xml")   @ResponseBody   public ResponseEntity<List<User>> getPartnersByDate(@RequestParam("type") String type, @RequestParam("id") String id) throws ParseException {   List<User> usersList = userService.getUsersByType(type);   return new ResponseEntity<List<User>>(usersList, HttpStatus.OK);}用户模型类：@Document(collection = "user")public class User { @Id private String id; private String email;}我该如何实施？

Answer 1

您可以创建一个新的对象来序列化：

class ResponseWrapper {

    private List<User> elements;

    ResponseWrapper(List<User> elements) {

        this.elements = elements;

    }

}

ResponseWrapper然后在你的控制器方法中返回一个实例：

   @RequestMapping(value = "/users", method = GET,produces = "application/xml")

   @ResponseBody

   public ResponseEntity<ResponseWrapper> getPartnersByDate(@RequestParam("type") String type, @RequestParam("id") String id) throws ParseException {

   List<User> usersList = userService.getUsersByType(type);

   ResponseWrapper wrapper = new ResponseWrapper(usersList);

   return new ResponseEntity<ResponseWrapper>(wrapper, HttpStatus.OK);

}