这个 python 程序应该检查匹配的字符串，但是在三个错误的输入之后，编程没有终止

Question

// 匹配字符串程序exact_word = "Guessing"    guess_kid = ""    guess_count = 0    guess_limit = 3    out_of_guesses = False    while guess_kid != exact_word.casefold() and not(out_of_guesses):        if guess_count < guess_limit:            guess_kid = input("Enter another word : ")            guess_count += 1    else:        out_of_guesses = True    if out_of_guesses:        print("Out of luck")    else:        print("you win")// 三个错误输入后程序没有终止

Answer 1

缩进是一种触动。尝试这个：

exact_word = "Guessing"

guess_kid = ""

guess_count = 0

guess_limit = 3

out_of_guesses = False

while guess_kid != exact_word.casefold() and not(out_of_guesses):

    if guess_count < guess_limit:

        guess_kid = input("Enter another word : ")

        guess_count += 1

    else:

        out_of_guesses = True

        if out_of_guesses:

            print("Out of luck")

        else:

            print("you win")

使用循环/子句后跟踪缩进很重要。由于我们没有在while:循环之前缩进，我将前 5 行移动到完全左对齐。

因为while:循环开始一个循环，所以下一个子句if和相应的else子句缩进一个。这些子句下的子集文本再次缩进。

希望这可以帮助！

Answer 2

exact_word = "Guessing"

guess_kid = ""

guess_count = 0

guess_limit = 3

out_of_guesses = False

while guess_kid != exact_word.casefold() and not(out_of_guesses):

    if guess_count < guess_limit:

        guess_kid = input("Enter another word : ")

        guess_count += 1

    else:

        out_of_guesses = True

if out_of_guesses:

        print("Out of luck")

else:

        print("you win")

这对你有用。一旦在 中进行了一些更改，您需要检查条件out_of_guesses。