在默认为任何运行时错误的异常处理程序之前，如何让@ExceptionHandlers 处理特定异常？

Question

我想使用 @ExceptionHandler 来处理任何 Hibernate 异常。如果异常不是 Hibernate 异常，则运行时错误的 @ExceptionHandler 会处理异常。问题是，运行时异常总是优先于 Hibernate 异常处理程序。意思是，发生的任何休眠异常都由通用运行时异常处理程序处理。如何确保 Hibernate 异常由其异常处理程序处理，而不是由运行时异常处理？    '@ExceptionHandler(HibernateException.class)public String handleHibernateException(HibernateException exc, Model theModel) {    String message = "An error has occured: " + exc.getLocalizedMessage() + "\n" + exc.getCause().toString()            + "\r\n";    myLogger.warning(message);    theModel.addAttribute("exception", message);    return "testing";}// handle any other runtime/unchecked exception and log it@ExceptionHandler(RuntimeException.class)public String handleRuntimeExceptions(RuntimeException exc, Model theModel) {    String message = "An error has occured: " + exc.getLocalizedMessage() + "\n" + exc.getCause().toString()            + "\r\n";    myLogger.warning(message);    theModel.addAttribute("exception", message);    return "testing";}'

Answer 1

您可以通过以下方式检查异常是否是 HibernateException 的实例：

@ExceptionHandler(RuntimeException.class)

public String handleRuntimeExceptions(RuntimeException exc, Model theModel) {

    if (exc instanceof HibernateException) {

        return handleHibernateException((HibernateException) exc.getCause(), theModel);

    } else if (exc.getCause() instanceof HibernateException) {

        HibernateException hibernateException = (HibernateException) exc.getCause();

        return handleHibernateException(hibernateException, theModel);

    }

    String message = "An error has occurred: " + exc.getLocalizedMessage() + "\n" + exc.getCause().toString() + "\r\n";

    myLogger.warning(message);

    theModel.addAttribute("exception", message);

    return "testing";

}