将项目从一个列表移动到另一个列表并删除字符串的某些部分

Question

我有这个带有 ID 和标题的列表myemails = [12345, 56789, 456789, 54321, 98765, 'Sample Title: Title number one', 'Sample Title: Title number two', 'Sample Title: Title number three', 'Sample Title: Title number four', 'Sample Title: Title number five']我正在寻找一种方法将此列表拆分为两个单独的列表，其中一个仅存储 ID，另一个标题中没有字符串的“示例标题：”部分：myemailId = [12345, 56789, 456789, 54321, 98765]myemailTitle = ['Title number one', 'Title number two', 'Title number three', 'Title number four', 'Title number five']到目前为止我的代码：from collections import defaultdictmyemails = [12345, 56789, 456789, 54321, 98765, 'Sample Title: Title number one', 'Sample Title: Title number two', 'Sample Title: Title number three', 'Sample Title: Title number four', 'Sample Title: Title number five'] d = defaultdict(myemails)for x in myList:   d[type(x)].append(x)emailId = print d[int]emailTitle = print  d[str]但是它会引发此错误：TypeError: first argument must be callable or None有人可以帮我吗？提前致谢！

Answer 1

利用：

myemailid = [item for item in myemails if str(item).isdigit()]

myemailtitle = [item.replace("Sample Title: ", "") for item in myemails if not str(item).isdigit()]

print(myemailid)

print(myemailtitle)

这打印：

[12345, 56789, 456789, 54321, 98765]

['Title number one', 'Title number two', 'Title number three', 'Title number four', 'Title number five']

Answer 2

您的代码中有几个问题

• defaultdict应该用类型初始化，但你用myemails而不是初始化它list

• 您将结果分配给print变量（print返回None）

试试这个：

myemails = [12345, 56789, 456789, 54321, 98765, 'Sample Title: Title number one', 'Sample Title: Title number two', 'Sample Title: Title number three', 'Sample Title: Title number four', 'Sample Title: Title number five'] 

ids = []

titles = []

for x in myemails:

    if type(x) == int:

        ids.append(x)  

    elif type(x) == str:

        titles.append(x)

    else:

        print("unsupported type {} of {}".format(type(x),x))

print(ids)

print(titles)