如何在python中使用re函数

Question

我有以下列表： ['[infotype02]', 'lastModifiedOn = serial<customMapping>', 'customString18 = BADGE_NUMBER<move>', 'firstName = FIRST_NAME<move>', 'lastName = LAST_NAME<move>', 'customString29 = USER_NAME<move>', 'email = EMAIL_ADDRESS<move>', 'documenttype = DOC_TYPE<move>', 'documentnumber = DOC_SERIA<customMapping>', 'documentnumberx2 = DOC_NUMBER<customMapping>', 'issuedate = DOC_ISSUE_DATE<move>', 'issueauthority = DOC_ISSUER<move>', 'nationalId = CNP<move>', 'company = COMPANY<move>', 'phoneNumber = PHONE_NUMBER<move>', 'startDate = HIRE_DATE<customMapping>', 'startDatex2 = TERMINATION_DATE<customMapping>', '[/infotype02]', '[infotype02]', 'lastModifiedOn = serial<customMapping>', 'customString18 = BADGE_NUMBER<move>', 'firstName = FIRST_NAME<move>', 'lastName = LAST_NAME<move>', 'customString29 = USER_NAME<move>', 'email = EMAIL_ADDRESS<move>', 'documenttype = DOC_TYPE<move>', 'documentnumber = DOC_SERIA<customMapping>', 'documentnumberx2 = DOC_NUMBER<customMapping>', 'issuedate = DOC_ISSUE_DATE<move>', 'issueauthority = DOC_ISSUER<move>', 'nationalId = CNP<move>', 'company = COMPANY<move>', 'phoneNumber = PHONE_NUMBER<move>', 'startDate = HIRE_DATE<customMapping>', 'startDatex2 = TERMINATION_DATE<customMapping>', '[/infotype02]']对于列表中的 i；我 =[infotype02]我尝试使用 re 表达式来获取 [] 之间的字符串，预期结果infotype02：        result = re.search('[(.*)]', i)然后尝试将 result.group(1) 附加到新列表并返回错误：    lst.append(result.group(1))     AttributeError: 'NoneType' object has no attribute 'group'我不明白我的 re 表达式有什么问题，为什么它没有找到 [] 之间的字符串

Answer 1

您可以使用一个简单for-loop的方法来完成此操作：

data = ['[infotype02]', 'lastModifiedOn = serial<customMapping>', 'customString18 = BADGE_NUMBER<move>', 'firstName = FIRST_NAME<move>', 

    'lastName = LAST_NAME<move>', 'customString29 = USER_NAME<move>', 'email = EMAIL_ADDRESS<move>', 'documenttype = DOC_TYPE<move>', 

    'documentnumber = DOC_SERIA<customMapping>', 'documentnumberx2 = DOC_NUMBER<customMapping>', 'issuedate = DOC_ISSUE_DATE<move>', 

    'issueauthority = DOC_ISSUER<move>', 'nationalId = CNP<move>', 'company = COMPANY<move>', 'phoneNumber = PHONE_NUMBER<move>', 

    'startDate = HIRE_DATE<customMapping>', 'startDatex2 = TERMINATION_DATE<customMapping>', '[/infotype02]', '[infotype02]', 

    'lastModifiedOn = serial<customMapping>', 'customString18 = BADGE_NUMBER<move>', 'firstName = FIRST_NAME<move>', 'lastName = LAST_NAME<move>',

    'customString29 = USER_NAME<move>', 'email = EMAIL_ADDRESS<move>', 'documenttype = DOC_TYPE<move>', 'documentnumber = DOC_SERIA<customMapping>', 

    'documentnumberx2 = DOC_NUMBER<customMapping>', 'issuedate = DOC_ISSUE_DATE<move>', 'issueauthority = DOC_ISSUER<move>', 'nationalId = CNP<move>', 

    'company = COMPANY<move>', 'phoneNumber = PHONE_NUMBER<move>', 'startDate = HIRE_DATE<customMapping>', 'startDatex2 = TERMINATION_DATE<customMapping>', 

    '[/infotype02]']

new_list = []

for d in data:

    if d[0] == '[' and not d[1] == '/':

    #if re.match(r"\[[^/](.*)\]", d): # If you want to use `re`

        new_list.append(d[1:-1])

print(new_list)

输出：

['infotype02', 'infotype02']

因为您在给定列表中有 2 个这些标签。