遍历对象数组并根据多个条件对其进行过滤

Question

我有一个包含大量重复/无用数据的对象数组。我需要根据客户 id 进行过滤并选择具有最新日期的对象。数据看起来像这样：let data = [  {    CUSTOMER_PERMANENT_ID: "2495",    EMAIL: "[e-mail]",    EVENT_ACTIVATION_TIME: "2019-10-25 13:57:38.79",  },  {    CUSTOMER_PERMANENT_ID: "2495",    EMAIL: "[e-mail]",    EVENT_ACTIVATION_TIME: "2019-10-28 20:04:49.016",  },  {    CUSTOMER_PERMANENT_ID: "2495",    EMAIL: "[e-mail]",    EVENT_ACTIVATION_TIME: "2019-10-28 20:04:49.019",  },  {    CUSTOMER_PERMANENT_ID: "5995",    EMAIL: "[e-mail]",    EVENT_ACTIVATION_TIME: "2019-10-28 17:24:10.98",  }]我尝试了以下功能，但它仅在有两个重复对象时才有效，如果有两个以上，则返回所有对象。public fixDcppSelectedClientData() {    let result = [];    for (let item of this.arr) {      for (let checkingItem of this.arr) {        if (          this.arr.indexOf(item) !=            this.arr.indexOf(checkingItem) &&          item.CUSTOMER_PERMANENT_ID == checkingItem.CUSTOMER_PERMANENT_ID &&          new Date(item.EVENT_ACTIVATION_TIME).getTime() <            new Date(checkingItem.EVENT_ACTIVATION_TIME).getTime()        ) {          if (result.indexOf(checkingItem) == -1) {            result.push(checkingItem);          }        }      }    }    console.log("filtered data is ", result);  }我需要更多地研究这个话题，但是如果有人能在此期间提供帮助，那就太好了。

Answer 1

let id = "2495"

const query = data

    .filter( obj => obj.CUSTOMER_PERMANENT_ID === id )

    .sort( (obj1, obj2) => 

        (obj1.EVENT_ACTIVATION_TIME < obj2.EVENT_ACTIVATION_TIME) ? 1 : -1 

    )

console.log('latest', query[0]);

console.log('second to latest', query[1]);

console.log('all with this id', query)

Answer 2

此代码过滤器重复 id

var newArr = data.filter((x, index, self) =>

  index === self.findIndex((t) => (

    t.CUSTOMER_PERMANENT_ID === x.CUSTOMER_PERMANENT_ID)));

console.log(newArr);