用户输入后如何重新启动while循环

Question

我刚刚开始编码，我正在慢慢理解它。对于我的班级，我们必须制作一个儿童程序来练习他们的数学，并询问他们是否愿意再试一次，如果它是正确的。如果他们输入 Y，我无法理解如何让我的 while True 循环重新启动。有什么提示吗？这是我的代码：    #Addition        A = int(input("What is %i + %i =" %(N1, N2)))        while add != N1 + N2:                 add = int(input("Incorrect, what is %i + %i = " %(N1,N2)))        while add == N1 + N2:                 repeat =(input("Correct! would you like to try again? Y/N "))        if repeat == 'n':                break        if repeat == 'y':                continueif op == "-":    #Subrtraction        s = int(input("What is %i - %i =" %(N1, N2)))        while s != N1 - N2:                 s = int(input("Incorrect, what is %i - %i = " %(N1,N2)))        while s == N1 - N2:                 repeat =(input("Correct! would you like to try again? Y/N "))if op == "*":     #Multiply        m = int(input("What is %i - %i =" %(N1, N2)))        while m != N1 * N2:                 m = int(input("Incorrect, what is %i - %i = " %(N1,N2)))        while m == N1 * N2:                 repeat =(input("Correct! would you like to try again? Y/N "))

Answer 1

我认为最好先进入一个while循环，然后从用户那里获取输入或确定答案是否正确以及其他问题......

# coding: utf-8

# Start of the 1st Question

redo="y"

A1=-1 # can be any integer but not the correct answer

n1, n2 = 2, 3

while (A1 != n1 + n2) or redo.lower()=="y":

    # ask the question

    A1 = int(input("What is the sum of %i and %i : " % (n1, n2)))

    # if answer is correct

    if A1 == n1 + n2:

        redo = input("Correct ! Would you like to try again? (Y/[N]) : ")

        if redo.lower() == "y":

            continue

        else:

            break

    else:

        print("Your Answer : %d is Incorrect!" % A1)

Answer 2

这种程序结构没有意义。

你可以做：

while True:

    num1 = int(input("num1 "))

    num2 = int(input("num2 "))

    op = '+'

    calc = -1

    if op == "+":

        while calc != num1 + num2:

            calc = int( input(f"Whats {num1} {op} {num2}?"))

    elif op == "-":

        pass # code the others 

    elif op == "*":

        pass # code the others 

    elif op == "/":

        pass # code the others - use float where needed instead of int 

        # comparing floats is difficult due to float math rounding imperfection

    print("Correct!" , num1, op, num2,"=",calc)

    again = input("Again? Y  to do it again: ").lower()

    if again != "y": 

        break    # leaves the while True

Answer 3

为此，您可以定义一个函数。也许它比你在课堂上做的要复杂一点，但它仍然很基础，所以你可以轻松学习它:) 使用函数时，请记住在第一次调用它以便它可以工作。这是一个例子：

def function_name():

    while True:

        '''your code'''

        repeat =(input("Correct! would you like to try again? Y/N "))

        if repeat == "y":

            function_name() # wach time the user say "y" the code calls the function again.

        break # the break will finish the while loop and will close the program.

function_name() # that's where I call the function the first time.

顺便说一句，如果您正在使用该函数，则实际上不必使用 while 循环。但我认为这是你在课堂上的工作，所以我就这样吧:)