删除正则表达式戈朗中第一次出现的匹配项

Question

我有以下字符串：new k8s.KubeRoleBinding(this, "argocd-application-controller", {    kind: "RoleBinding",    metadata: {        labels: {            "app.kubernetes.io/component": "application-controller",            "app.kubernetes.io/name": "argocd-application-controller",            "app.kubernetes.io/part-of": "argocd",        },        name: "argocd-application-controller",    },    roleRef: {        apiGroup: "rbac.authorization.k8s.io",        kind: "Role",        name: "argocd-application-controller",    },    subjects: [{        kind: "ServiceAccount",        name: "argocd-application-controller",    }],});ID 喜欢删除第一次出现kind:到目前为止，我尝试了以下内容，但它删除了所有出现的情况。    re := regexp.MustCompile("(?m)[\r\n]+^.*kind.*$")    res := re.ReplaceAllString(str, "$1")带代码的游乐场链接 ： https://play.golang.org/p/SMiyTJvKNVF通缉字符串 ：new k8s.KubeRoleBinding(this, "argocd-application-controller", {    metadata: {        labels: {            "app.kubernetes.io/component": "application-controller",            "app.kubernetes.io/name": "argocd-application-controller",            "app.kubernetes.io/part-of": "argocd",        },        name: "argocd-application-controller",    },    roleRef: {        apiGroup: "rbac.authorization.k8s.io",        kind: "Role",        name: "argocd-application-controller",    },    subjects: [{        kind: "ServiceAccount",        name: "argocd-application-controller",    }],});

Answer 1

找到第一个匹配项的位置。使用字符串切片操作删除匹配项。

loc := re.FindStringIndex(str)

res := str

if loc != nil {

    res = str[:loc[0]] + str[loc[1]:]

}

在操场上运行该示例。