如果日期匹配，则将项推送到数组中 - 脚本/类型脚本

Question

做空数组以显示它们相对于日期，就像我所做的那样 - 徒步旅行，在2020-05-10购物和徒步旅行，在2020-05-10上足球和其他日期类似。 const items = [ {title: 'Hiking', date: new Date('2020-05-10')}, {title: 'Shopping', date: new Date('2020-05-10')}, // {title: 'Hiking', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2019-05-22')}, // {title: 'Football', date: new Date('2020-05-28')}, {title: 'Hiking', date: new Date('2020-05-28')}, {title: 'Cricket', date: new Date('2020-05-28')},];

Answer 1

您需要使用 。reduce()

var items = [ {title: 'Hiking', date: new Date('2020-05-10')}, {title: 'Shopping', date: new Date('2020-05-10')},{title: 'Hiking', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2020-05-22')}, {title: 'Football', date: new Date('2020-05-28')}, {title: 'Hiking', date: new Date('2020-05-28')}, {title: 'Cricket', date: new Date('2020-05-28')}];

var result = items.reduce((acc, {title, date})=>{

    dateKey = new Date(date).toISOString().slice(0,10);

    acc[dateKey] = acc[dateKey] || [];

    acc[dateKey].push({title});

    return acc;

},{});

console.log(result);

Answer 2

试试这个

let items = [

      {title: 'Hiking', date: new Date('2020-05-10')},

      {title: 'Shopping', date: new Date('2020-05-10')},

      {title: 'Hiking', date: new Date('2020-05-22')},

      {title: 'Football', date: new Date('2019-05-22')},

      {title: 'Football', date: new Date('2020-05-28')},

      {title: 'Hiking', date: new Date('2020-05-28')},

      {title: 'Cricket', date: new Date('2020-05-28')},

     ];

    items.sort(function(a,b){

      return a.date - b.date;

    });

    console.log(items);