条件语句：不确定为什么它会得到未定义的结果 （JavaScipt ）

Question

我是JavaScript的新手，我只是在学习基本的，不知道为什么只有一半的代码可以工作。var quartet = ["abasd", "bsdfa", "ccvssw"];console.log("quartet.length : " + quartet.length);console.log(quartet[0]);console.log(quartet[1]);console.log(quartet[2]);if (quartet.length = 1) {    console.log("It's just a Solo");} else if (quartet.length = 2) {    console.log("It's just a Duo");} else if (quartet.length = 3) {    console.log("It's just a Trio");} else if (quartet.length = 4) {    console.log("Perfect, a quartet, just right");} else {    console.log("Either too many or nobody");};for (var i = 0; i <= quartet.length; i++) {    console.log(quartet[i] + " : " + i)};但是，任何使此条件语句在 VS Code 内部工作的尝试都会导致quartet.length : 3abasdbsdfaccvsswIt's just a Soloabasd : 0undefined : 1

Answer 1

您需要使用（或，最好）进行比较;使用 = 将分配给四重奏长度，这将截断数组。=====

所以

if (quartet.length == 1) {

等。

Answer 2

您应该使用 而不是 来比较数字。此外，条件应为 ：而不是：===for loopi < quartet.lengthi <= quartet.length

var quartet = ["abasd", "bsdfa", "ccvssw"];

console.log("quartet.length : " + quartet.length);

console.log(quartet[0]);

console.log(quartet[1]);

console.log(quartet[2]);

if (quartet.length == 1) {

    console.log("It's just a Solo");

} else if (quartet.length == 2) {

    console.log("It's just a Duo");

} else if (quartet.length == 3) {

    console.log("It's just a Trio");

} else if (quartet.length == 4) {

    console.log("Perfect, a quartet, just right");

} else {

    console.log("Either too many or nobody");

};

for (var i = 0; i < quartet.length; i++) {

    console.log(quartet[i] + " : " + i)

};