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如何洗牌用二维阵列制作的套牌

如何洗牌用二维阵列制作的套牌

慕妹3242003 2022-09-07 17:35:07
我在洗牌两副牌时遇到问题。我使用二维数组创建了两个套牌。请记住,这些是要求。我还需要使用一种名为shuffle()的方法对它们进行洗牌,该方法接收1D数组并返回1D数组。在洗牌两副牌后,我需要从第一副牌中挑选前两张牌,从第二副牌中挑选前两张牌,并检查它们是否匹配。以及获得结果所需的洗牌次数。示例输出:第1副牌中的两张完全匹配卡牌是:钻石王牌,俱乐部2张第2副牌中的两张完全匹配卡牌是:钻石王牌,俱乐部2张洗牌次数: 387这是我们参与的项目的第二部分,下面是我试图解决这个问题的内容。我尝试使用下面的代码创建套牌,这有效int[][] deck = new int[2][52];for (int i = 0; i <= deck.length - 1; i++) {    for (int j = 0; j < deck[i].length; j++) {        deck[i][j] = j;    }}我写了洗牌方法,但它似乎不起作用。public static int[] shuffle(int[] deck) {  for(int i=0; i<deck.length; i++) {    int index = (int)(Math.random()* deck.length);   int temp = deck[i];    deck[i] = deck[index];  deck[index] = temp;  }return deck;    }下面的代码是本项目第一部分的原始代码,在对它进行洗牌并计算获得四个这样的代码之后,我们需要从一个甲板上打印四个这样的代码。class Main {  public static void main(String[] args) {  String[] suit = { "Spades", "Hearts", "Diamond", "Clubs" };  String[] rank = { "Ace", "1", "2", "3", "4",                  "5", "6", "7", "8", "9",                 "10", "Jack", "Queen", "King" };  int rank1, rank2, rank3, rank4, suit1, suit2, suit3, suit4, count = 0;   int[] deck = new int[52];  for (int i = 0; i < deck.length; i++) {     deck[i] = i;  }  do {    count++;    for (int i = 0; i < deck.length; i++) {       int index = (int) (Math.random() * deck.length);       int temp = deck[i];       deck[i] = deck[index];       deck[index] = temp;    }    suit1 = deck[0] / 13;    suit2 = deck[1] / 13;    suit3 = deck[2] / 13;    suit4 = deck[3] / 13;    rank1 = deck[0] % 13;    rank2 = deck[1] % 13;    rank3 = deck[2] % 13;    rank4 = deck[3] % 13;  } while (rank1 != rank2 || rank2 != rank3 || rank3 != rank4);    System.out.println(" Four-of-kind cards: " + suit[suit1] + " of "        + rank[rank1] + ", " + suit[suit2] + " of " + rank[rank2]        + ", " + suit[suit3] + " of " + rank[rank3] + ", "        + suit[suit4] + " of " + rank[rank4]        + "\n Number of shuffled times: " + count);    }}结果应该再次如下所示。示例输出:来自卡组1的两张精确匹配卡是:钻石王牌,俱乐部2卡组2中的两张精确匹配卡牌是:钻石王牌,俱乐部2洗牌次数: 387
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精慕HU

TA贡献1845条经验 获得超8个赞

您的方法是正确的。无需执行另一个将接受 2D 数组的 shuffle 方法。您只需要在2D阵列的每个套牌中调用该方法即可。要做到这一点,只需:shuffleshuffle


deck[0] = shuffle(deck[0]);

deck[1] = shuffle(deck[1]);

我还更新了您的代码,以便在出现其他要求时可以更轻松地进行修改。请参考以下代码:


public class Main {

    public static String[] card; // The holder for all cards


    public static void main(String[] args) {

        card = generateCardSuits(); // generate the cards with their corresponding suits

        doPartOne();

        doPartTwo();

    }


    /**

     * Part One

     *

     */

    public static void doPartOne() {

        System.out.println("========== PART ONE ==========");

        int[] deck = generateAndShuffleInitialDeck();

        int ctr = 1;

        while (true) {

            if (deck[0] % 13 == deck[1] % 13 && deck[1] % 13 == deck[2] % 13 && deck[2] % 13 == deck[3] % 13) {

                break;

            }

            deck = shuffle(deck);

            ctr++;

        }

        System.out.println("Four-of-kind cards are: " + card[deck[0]] + " , " + card[deck[1]] + " , " + card[deck[2]]

                + " and " + card[deck[3]]);

        System.out.println("Number of shuffled times: " + ctr);

        System.out.println("==============================");

    }


    /**

     * Part Two

     *

     */

    public static void doPartTwo() {

        System.out.println("========== PART TWO ==========");

        int[][] deck = new int[2][52];

        deck[0] = generateAndShuffleInitialDeck();

        deck[1] = generateAndShuffleInitialDeck();


        int ctr = 1;

        while (deck[0][0] != deck[1][0] || deck[0][1] != deck[1][1]) {

            deck[0] = shuffle(deck[0]);

            deck[1] = shuffle(deck[1]);

            ctr++;

        }


        System.out.println("Two exact match cards from deck 1 are: " + card[deck[0][0]] + " and " + card[deck[0][1]]);

        System.out.println("Number of shuffled times: " + ctr);

        System.out.println("==============================");

    }


    /**

     * Generate an initial deck of cards and shuffle them

     *

     * @return The initial and shuffled deck of cards

     */

    public static int[] generateAndShuffleInitialDeck() {

        int[] deck = new int[52];


        for (int j = 0; j < deck.length; j++) {

            deck[j] = j;

        }

        return shuffle(deck);

    }


    /**

     * Generate the cards with their corresponding suits

     *

     * @return The deck that will serve as the mapper for the cards to their suits

     */

    public static String[] generateCardSuits() {

        String[] rank = { "Ace", "2", "3", "4", "5", "6", "7", "8", "9", "10", "Jack", "Queen", "King" };

        String[] suit = { "Spades", "Hearts", "Diamond", "Clubs" };


        String[] cards = new String[52];


        for (int i = 0, j = 0, s = 0; i < cards.length; i++) {

            cards[i] = rank[j] + " of " + suit[s];

            j++;

            if (j == 13) { // Since each suit consist of 13 cards

                j = 0;

                s++;

            }

        }

        return cards;

    }


    /**

     * Shuffle the deck of cards

     *

     * @param deck

     *            the deck of cards to be shuffle

     *

     * @return The shuffled deck of cards

     */

    public static int[] shuffle(int[] deck) {

        for (int i = 0; i < deck.length; i++) {

            int index = (int) (Math.random() * deck.length);

            int temp = deck[i];

            deck[i] = deck[index];

            deck[index] = temp;

        }

        return deck;

    }

}



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反对 回复 2022-09-07
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