打印元素列表对的所有可能组合

Question

我有一个python中的元组列表。list = [(1,2), (1,3), (1,4), (2,3), (2, 4), (3,4)]如何打印所有可能的元组对？我想避免重复。例如 ，（1，2）、（2，3） 和 （2，3）、（1，2） 是重复的。预期结果是：(1,2), (1,3)(1,2), (1,4)(1,2), (2,3)(1,2), (2,4)(1,2), (3,4)(1,3), (1,4)(1,3), (2,3)(1,3), (2,4)(1,3), (3,4)(1,4), (2,3)(1,4), (2,4)(1,4), (3,4)(2,3), (2,4)(2,3), (3,4)(2,4), (3,4)

Answer 1

看看迭代工具中的组合。

>>> l = [(1,2), (1,3), (1,4), (2,3), (2, 4), (3,4)]

>>> import itertools

>>> combinations = itertools.combinations(l, 2)

>>> for combination in combinations:

...   print(combination)

...

((1, 2), (1, 3))

((1, 2), (1, 4))

((1, 2), (2, 3))

((1, 2), (2, 4))

((1, 2), (3, 4))

((1, 3), (1, 4))

((1, 3), (2, 3))

((1, 3), (2, 4))

((1, 3), (3, 4))

((1, 4), (2, 3))

((1, 4), (2, 4))

((1, 4), (3, 4))

((2, 3), (2, 4))

((2, 3), (3, 4))

((2, 4), (3, 4))

Answer 2

试试这个代码：

from itertools import combinations 

# Get all combinations and length 2 

comb = combinations([(1,2), (1,3), (1,4), (2,3), (2, 4), (3,4)], 2) 

# Print the obtained combinations 

for i in list(comb): 

    print(i[0],",", i[1])

输出：

(1, 2) , (1, 3)

(1, 2) , (1, 4)

(1, 2) , (2, 3)

(1, 2) , (2, 4)

(1, 2) , (3, 4)

(1, 3) , (1, 4)

(1, 3) , (2, 3)

(1, 3) , (2, 4)

(1, 3) , (3, 4)

(1, 4) , (2, 3)

(1, 4) , (2, 4)

(1, 4) , (3, 4)

(2, 3) , (2, 4)

(2, 3) , (3, 4)

(2, 4) , (3, 4)