如何检查数组是否具有具有特定属性的对象，然后找到该属性？

Question

我有一个数组，看起来像这样：var arr = [  {name: "Joe", id: "p01"}];我想首先检查输入是否与具有相同属性的任何内容匹配。例如，如果用户输入“Steven”，我希望它检查名称为“Steven”的任何对象。name其次，我想得到他们输入的任何东西，如果存在的话。id抱歉，如果这是一个很大的要求。

Answer 1

const arr = [

  {name: "Joe", id: "p01"}

];

//need to find array item where object.name is Joe - https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/find

const obj = arr.find(item => {

    //item = {name: "Joe", id: "p01"}

    return item.name === 'Joe'

});

//obj = {name: "Joe", id: "p01"}

//check if item exists and return id value;

const id = obj && obj.id;

//to filter array and get only items where name is Joe - https://developer.mozilla.org/en-US/docs/Web/JavaScript/Reference/Global_Objects/Array/filter

const items = arr.filter(item => item.name === 'Joe');

//items = [{name: "Joe", id: "p01"}]

//to get the list of ids with condition

const ids = arr.reduce((results, obj) => {

 if (obj.name === "Joe") results.push(obj.id);

}, [])

//ids = ["p01"]

//one line solution

const { id } = arr.find(item => item.name === 'Joe') || {};

Answer 2

它也可以做到。filter

var arr = [

  {name: "Joe", id: "p01"},

  {name: "Steve", id: "p02"},

  {name: "Smith", id: "p01"},

];

console.log(arr.filter(i=>i.name.includes('Ste')))

   var ids = arr.filter(i=>i.name.includes('Ste')).map(k=>k.id);

console.log(ids);

Answer 3

你可以这样做，希望这会帮助你

let arr = [

  {name: "Joe", id: "p01"}

];

let searchQuery = 'Joe'

let finalResult = arr.find(({name}) => name.includes(searchQuery));

finalResult = (finalResult && finalResult.id) ? finalResult.id :"No Match Found"

console.log(finalResult);

Answer 4

const foundItem = arr.find(item => item.name === searchQuery) // searchQuery = Steven

if (foundItem === -1) {

  console.log("Item not found")

} else {

  console.log("Item found", foundItem)

  console.log("Item id: ", fountItem.id)

}