我正在使用Golang gorilla / mux包,其中一个例子如下:func main() { var wait time.Duration flag.DurationVar(&wait, "graceful-timeout", time.Second * 15, "the duration for which the server gracefully wait for existing connections to finish - e.g. 15s or 1m") flag.Parse() r := mux.NewRouter() // Add your routes as needed srv := &http.Server{ Addr: "0.0.0.0:8080", // Good practice to set timeouts to avoid Slowloris attacks. WriteTimeout: time.Second * 15, ReadTimeout: time.Second * 15, IdleTimeout: time.Second * 60, Handler: r, // Pass our instance of gorilla/mux in. } // Run our server in a goroutine so that it doesn't block. go func() { if err := srv.ListenAndServe(); err != nil { log.Println(err) } }() c := make(chan os.Signal, 1) // We'll accept graceful shutdowns when quit via SIGINT (Ctrl+C) // SIGKILL, SIGQUIT or SIGTERM (Ctrl+/) will not be caught. signal.Notify(c, os.Interrupt) // Block until we receive our signal. <-c // Create a deadline to wait for. ctx, cancel := context.WithTimeout(context.Background(), wait) defer cancel() // Doesn't block if no connections, but will otherwise wait // until the timeout deadline. srv.Shutdown(ctx) // Optionally, you could run srv.Shutdown in a goroutine and block on // <-ctx.Done() if your application should wait for other services // to finalize based on context cancellation. log.Println("shutting down") os.Exit(0)}这似乎很简单,但我的理解是,在调用时,延迟不会运行(根据 https://gobyexample.com/exit)。我注意到有一个返回的 by ,然后被推迟。我的猜测是,如果在截止日期之前完成,这应该取消上面创建的上下文,但我不明白在最后调用时会如何发生这种情况。任何人都可以帮我看到我错过了什么吗?os.Exit()CancelFunc()context.WithTimeout()main()os.Exit()
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