Javascript ：如何使用onclick填写多个输入

Question

使用onclick按钮，我如何填写页面中包含toinput id的所有输入。在这个简单的代码段中，您可以看到只填写了第一个输入。如何通过一键填写这2个输入，当我启动模式。function getid(id){   $('#toinput').val(id);}<script src="https://code.jquery.com/jquery-3.2.1.slim.min.js" integrity="sha384-KJ3o2DKtIkvYIK3UENzmM7KCkRr/rE9/Qpg6aAZGJwFDMVNA/GpGFF93hXpG5KkN" crossorigin="anonymous"></script><script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.12.9/umd/popper.min.js" integrity="sha384-ApNbgh9B+Y1QKtv3Rn7W3mgPxhU9K/ScQsAP7hUibX39j7fakFPskvXusvfa0b4Q" crossorigin="anonymous"></script><script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/js/bootstrap.min.js" integrity="sha384-JZR6Spejh4U02d8jOt6vLEHfe/JQGiRRSQQxSfFWpi1MquVdAyjUar5+76PVCmYl" crossorigin="anonymous"></script><link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous"><!-- Button trigger modal --><button onclick=(getid(10)) type="button" class="btn btn-primary" data-toggle="modal" data-target="#exampleModal">  Launch demo modal</button><!-- Modal --><div class="modal fade" id="exampleModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">  <div class="modal-dialog" role="document">    <div class="modal-content">      <div class="modal-header">        <h5 class="modal-title" id="exampleModalLabel">Modal title</h5>        <button type="button" class="close" data-dismiss="modal" aria-label="Close">          <span aria-hidden="true">&times;</span>        </button>      </div>      <div class="modal-body">        <input id="toinput" value="">        <input id="toinput" value="">      </div>      <div class="modal-footer">        <button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>        <button type="button" class="btn btn-primary">Save changes</button>      </div>    </div>  </div></div>

Answer 1

这恰恰是针对all inputs in your page that start with toinput id

function getid(id){

$("input[id^='toinput']").val(id)

}

<script src="https://code.jquery.com/jquery-3.2.1.slim.min.js" integrity="sha384-KJ3o2DKtIkvYIK3UENzmM7KCkRr/rE9/Qpg6aAZGJwFDMVNA/GpGFF93hXpG5KkN" crossorigin="anonymous"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.12.9/umd/popper.min.js" integrity="sha384-ApNbgh9B+Y1QKtv3Rn7W3mgPxhU9K/ScQsAP7hUibX39j7fakFPskvXusvfa0b4Q" crossorigin="anonymous"></script>

<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/js/bootstrap.min.js" integrity="sha384-JZR6Spejh4U02d8jOt6vLEHfe/JQGiRRSQQxSfFWpi1MquVdAyjUar5+76PVCmYl" crossorigin="anonymous"></script><link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">

<!-- Button trigger modal -->

<button onclick=(getid(10)) type="button" class="btn btn-primary" data-toggle="modal" data-target="#exampleModal">

  Launch demo modal

</button>

<!-- Modal -->

<div class="modal fade" id="exampleModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">

  <div class="modal-dialog" role="document">

    <div class="modal-content">

      <div class="modal-header">

        <h5 class="modal-title" id="exampleModalLabel">Modal title</h5>

        <button type="button" class="close" data-dismiss="modal" aria-label="Close">

          <span aria-hidden="true">&times;</span>

        </button>

      </div>

      <div class="modal-body">

        <input id="toinput_0" value="">

        <input id="toinput_1" value="">

      </div>

      <div class="modal-footer">

        <button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>

        <button type="button" class="btn btn-primary">Save changes</button>

      </div>

    </div>

  </div>

</div>

Answer 2

您的所有代码都是正确的，但您使用了两个ID。并且 id 必须是唯一的。为了解决您的问题，我所做的就是将id与class切换。因为类可以重复。您的代码的工作原理如下图所示。

function getid(id){

    $('.toinput').val(id);

}

<script src="https://code.jquery.com/jquery-3.2.1.slim.min.js" integrity="sha384-KJ3o2DKtIkvYIK3UENzmM7KCkRr/rE9/Qpg6aAZGJwFDMVNA/GpGFF93hXpG5KkN" crossorigin="anonymous"></script>

<script src="https://cdnjs.cloudflare.com/ajax/libs/popper.js/1.12.9/umd/popper.min.js" integrity="sha384-ApNbgh9B+Y1QKtv3Rn7W3mgPxhU9K/ScQsAP7hUibX39j7fakFPskvXusvfa0b4Q" crossorigin="anonymous"></script>

<script src="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/js/bootstrap.min.js" integrity="sha384-JZR6Spejh4U02d8jOt6vLEHfe/JQGiRRSQQxSfFWpi1MquVdAyjUar5+76PVCmYl" crossorigin="anonymous"></script><link rel="stylesheet" href="https://maxcdn.bootstrapcdn.com/bootstrap/4.0.0/css/bootstrap.min.css" integrity="sha384-Gn5384xqQ1aoWXA+058RXPxPg6fy4IWvTNh0E263XmFcJlSAwiGgFAW/dAiS6JXm" crossorigin="anonymous">

<!-- Button trigger modal -->

<button onclick=(getid(10)) type="button" class="btn btn-primary" data-toggle="modal" data-target="#exampleModal">

  Launch demo modal

</button>

<!-- Modal -->

<div class="modal fade" id="exampleModal" tabindex="-1" role="dialog" aria-labelledby="exampleModalLabel" aria-hidden="true">

  <div class="modal-dialog" role="document">

    <div class="modal-content">

      <div class="modal-header">

        <h5 class="modal-title" id="exampleModalLabel">Modal title</h5>

        <button type="button" class="close" data-dismiss="modal" aria-label="Close">

          <span aria-hidden="true">&times;</span>

        </button>

      </div>

      <div class="modal-body">

        <input class="toinput" value="">

        <input class="toinput" value="">

      </div>

      <div class="modal-footer">

        <button type="button" class="btn btn-secondary" data-dismiss="modal">Close</button>

        <button type="button" class="btn btn-primary">Save changes</button>

      </div>

    </div>

  </div>

</div>

Answer 3

您为两个输入提供相同的 ID，但它应始终是唯一的。相反，如果它不干扰你的css，就把它们俩的id都改成class=“toinput”，并修改你的jquery代码：

$('.toinput').val(id);

您也可以将 div 的类用于此目的，如下所示：

$('.modal-body input').val(id);