MultiValueDictKeyError at /add， Request method ：

Question

这是我 views.py 文件from django.shortcuts import renderdef home(request):    return render(request, 'home.html',{'name':'irtiza'})def add(request):val1 = int(request.GET['num1'])val2 = int(request.GET['num2'])res = val1 + val2return render(request, "result.html",{'result': res})当我运行此代码时，我收到此错误，错误然后我尝试了这个代码：def add(request):    val1 = int(request.GET.get(['num1']))    val2 = int(request.GET.get(['num2']))    res = val1 + val2    return render(request, "result.html",{'result': res})发生此错误。在此输入图像描述urls.py 文件from django.urls import path from . import viewsurlpatterns = [    path("",views.home,name="home"),    path("add", views.add, name="add")]首页.html 文件{% extends 'base.html' %}{% block content %}<h1> hello  {{name}} </h1><form action="add">    {% csrf_token %}    Enter 1st number : <input type="text" name="num1"><br>    Enter 2nd number : <input type="text" name="num2"><br>    <input type="submit"></form>{% endblock %}结果.html文件{% extends 'base.html' %}{% block content %}    Result : {{result}}{% endblock %}当我尝试POST功能时，它会给出下面提到的错误from django.shortcuts import render# Create your views here.def home(request):    return render(request, 'home.html',{'name':'irtiza'})def add(request):    val1 = int(request.POST['num1'])    val2 = int(request.POST['num2'])    res = val1 + val2    return render(request, "result.html",{'result': res})MultiValueDictKeyError at /add 'num1' Request Method： GET Request URL： http://127.0.0.1:7000/add?csrfmiddlewaretoken=t6mVWboKI37vxW3zDbVmpnB3j3g89EzjFhikDDMrB4qVEfrNyqG5pebeXgDLAFE0&num1=3&num1=3 Django Version： 3.0.3 Exception Type： MultiValueDictKeyError Exception Value：'num1' Exception Location： C：\Users\irtiza\AppData\Local\Continuum\anaconda3\lib\site-packages\django\utils\datastructures.py in getitem， 第 78 行 Python 可执行文件： C：\Users\irtiza\AppData\Local\Continuum\anaconda3\python.exe Python 版本： 3.7.4我现在应该做什么来解决这个错误。这只是一个将两个数字相加的简单函数。请帮帮我。

Answer 1

您在网址中经过两次，如下所示...num1

url - http://127.0.0.1:7000/add?csrf.......&num1=2&num1=3

改变它吹...

url - http://127.0.0.1:7000/add?csrf.......&num1=2&num2=3

并通过以下方式获得它...

def add(request):

    val1 = int(request.GET.get('num1'))

    val2 = int(request.GET.get('num2'))

    res = val1 + val2

    return render(request, "result.html",{'result': res})

并从您的表单更改此行，如下所示...

Enter 2nd number : <input type="text" name="num2"><br>

Answer 2

删除方括号。它不是必需的。

val1 = int(request.GET.get('num1'))
val2 = int(request.GET.get('num2'))

Answer 3

基本上我在家里的形式上失踪了（方法=“post或GET”）.html

我所做的更改包括：

家.html

{% extends 'base.html' %}

{% block content %}

<h1> hello  {{name}} </h1>

<form action="add" method="POST">

    {% csrf_token %}

    Enter 1st number : <input type="text" name="num1"><br>

    Enter 2nd number : <input type="text" name="num2"><br>

    <input type="submit">

</form>

{% endblock %}

views.py

from django.shortcuts import render

def home(request):

    return render(request, 'home.html',{'name':'irtiza'})

def add(request):

val1 = int(request.POST['num1'])

val2 = int(request.POST['num2'])

res = val1 + val2

return render(request, "result.html",{'result': res})

然后它工作正常。