1 回答
TA贡献1909条经验 获得超7个赞
如果分析OP码,起点和终点重合,因此在同一位置的2个点之间绘制一条线时,只会绘制一个点。逻辑是将第 i 步中获得的点与 (i+1) 个点连接起来。
要执行上述操作,最简单的方法是使用QPainterPath:
import sys
from PyQt5 import QtWidgets, QtGui, QtCore
class MyWidget(QtWidgets.QWidget):
def __init__(self):
super().__init__()
self.initUI()
self.paths = []
def initUI(self):
self.setGeometry(200, 200, 1000, 500)
self.label = QtWidgets.QLabel(self)
self.show()
def paintEvent(self, event):
qp = QtGui.QPainter(self)
for path in self.paths:
qp.drawPath(path)
def mousePressEvent(self, event):
path = QtGui.QPainterPath()
path.moveTo(event.pos())
self.paths.append(path)
super().mousePressEvent(event)
def mouseMoveEvent(self, event):
self.paths[-1].lineTo(event.pos())
self.label.setText('Coordinates: ( %d : %d )' % (event.x(), event.y()))
self.label.adjustSize()
self.update()
super().mouseMoveEvent(event)
def mouseReleaseEvent(self, event):
self.paths[-1].lineTo(event.pos())
self.update()
super().mouseReleaseEvent(event)
if __name__ == "__main__":
app = QtWidgets.QApplication(sys.argv)
window = MyWidget()
window.resize(800, 600)
sys.exit(app.exec_())
添加回答
举报