此脚本是一个函数,用于定义站点 URL 以将其发送到大脚本,但由于它是共享托管的,因此它获得了不正确的路径,如何告诉它正确的站点路径?我想直接告诉它站点网址和脚本目录,脚本认为这是路径,但正确的路径只是。我想删除,因为是共享主机路径/hermes/bosnaweb23a/index.php/index.php/hermes/bosnaweb23a//hermes/bosnaweb23a/<?php function home_base_url(){ $base_url = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS']!='off') ? 'https://' : 'http://'; $tmpURL = dirname(__FILE__); $tmpURL = str_replace(chr(92),'/',$tmpURL); $tmpURL = str_replace($_SERVER['DOCUMENT_ROOT'],'',$tmpURL); $tmpURL = ltrim($tmpURL,'/'); $tmpURL = rtrim($tmpURL, '/'); if (strpos($tmpURL,'/')){ $tmpURL = explode('/',$tmpURL); $tmpURL1 = $tmpURL[0]; $tmpURL2 = $tmpURL[1]; $tmpURL = $tmpURL1; if(!empty($tmpURL2)) $tmpURL .= '/'.$tmpURL2; } if ($tmpURL !== $_SERVER['HTTP_HOST']) $base_url .= $_SERVER['HTTP_HOST'].'/'.$tmpURL.'/'; else $base_url .= $tmpURL.'/'; $base_url = str_replace('//','/',$base_url); $base_url = str_replace('http:/','http://',$base_url); $base_url = str_replace('https:/','https://',$base_url); return str_replace(dirname(__FILE__),'',$base_url); } $local_path = dirname(__FILE__).'/'; $sSoftware = strtolower( $_SERVER["SERVER_SOFTWARE"] ); function getSlashes() { $sSoftware = strtolower( $_SERVER["SERVER_SOFTWARE"] ); if ( strpos($sSoftware, "microsoft-iis") !== false ) return "\\"; else return "/"; } if ( strpos($sSoftware, "microsoft-iis") !== false ) { $local_path = str_replace(getSlashes(), '/', dirname(__FILE__)).'/'; } function get_domain() { return $_SERVER['HTTP_HOST']; }
1 回答
慕工程0101907
TA贡献1887条经验 获得超5个赞
您可以使用此代码从 中获取。index.php/hermes/bosnaweb23a/index.php
$url = explode("/", "/hermes/bosnaweb23a/index.php");
$script_name = end($url);
$script_name将。index.php
- 1 回答
- 0 关注
- 105 浏览
添加回答
举报
0/150
提交
取消