2 回答
TA贡献1752条经验 获得超4个赞
错误是因为是类函数。findTarget
所以,你有这个:
test ob = new test();
String testing = findTarget(target1, source1);
...应更改为从静态上下文调用函数:
//test ob = new test(); not needed, the function is static
int testing = test.findTarget(target1, source1);
// also changed the testing type from String to int, as int IS findTarget's return type.
我没有您的文件内容进行试运行,但这至少应该有助于克服错误。
===== 更新:
你离你很近!
在main中,更改循环中的代码,使其如下所示:
String target1;
int testing = 0; // move and initialize testing here
while ((target1 = br.readLine()) != null) //as long the condition is not null it will keep printing.
{
//System.out.println(target1);
testing += test.findTarget(target1, source1);
//target1 = br.readLine();
}
System.out.println("answer is: "+testing);
TA贡献1993条经验 获得超5个赞
我终于能够解决我的问题。但扩展了功能。我想将加法递增 1。但是在我的编程中,它不断给我输出
答案是:1 答案是:1
相反,我希望我的程序打印的不是两个1,而是1 + 1 = 2
有人可以解决这个递增的问题吗?
import java.io.BufferedReader;
import java.io.File;
import java.io.FileReader;
import java.io.IOException;
import java.util.*;
public class test {
public static int findTarget(String target, String source) {
int target_len = target.length();
int source_len = source.length();
int add = 0;
// this function checks the character whether it is present.
for (int i = 0; i < source_len; ++i) // i is a varialbe used to count upto source_len.
{
int j = 0; // take another variable to count loops
while (add == 0)
{
if (j >= target_len) // count upto target length
{
break;
}
else if (target.charAt(j) != source.charAt(i + j))
{
break;
}
else
{
++j;
if (j == target_len)
{
add++; // this will return 1: true
}
}
}
}
return add;
//System.out.println(""+add);
}
public static void main(String... args) {
//String target = "for";
// function 1
try {
// read the file
Scanner sc = new Scanner(System.in);
System.out.println("Enter your review: ");
String source1 = sc.nextLine();
//String source1 = "Searching for a string within a string the hard way.";
File file = new File("write.txt"); //establising a file object
BufferedReader br = new BufferedReader(new FileReader(file)); //reading the files from the file object "file"
String target1;
while ((target1 = br.readLine()) != null) //as long the condition is not null it will keep printing.
{
//System.out.println(target1);
int testing = test.findTarget(target1, source1);
System.out.println("answer is: "+testing);
//target1 = br.readLine();
}
br.close();
}
catch (IOException e)
{
System.out.println("file error!");
}
}
}
添加回答
举报