是否可以使用/写入bufio。作家？

Question

要么我必须像这样写一个int16：delay :=  uint16(200)buf = new(bytes.Buffer)err = binary.Write(buf, encoding, delay)if err != nil {    panic(fmt.Sprint("binary.Write failed:", err))}_, _ = writer.Write(buf.Bytes())...或者和int64，像这样：nbObjects :=  uint64(len(myArray))buf = new(bytes.Buffer)err = binary.Write(buf, encoding, nbObjects)_, _ = writer.Write(buf.Bytes())..或类似的字符串：now := []byte(time.Now().Format("2006-01-02T15:04:05-0700"))buf = new(bytes.Buffer)err = binary.Write(buf, encoding, now)if err != nil {    panic(fmt.Sprint("binary.Write failed:", err))}_, _ = writer.Write(buf.Bytes())我可能有很多事情要做，但相同的“共享”代码总是：buf = new(bytes.Buffer)err = binary.Write(buf, encoding, [my variable])if err != nil {    panic(fmt.Sprint("binary.Write failed:", err))}_, _ = writer.Write(buf.Bytes())有没有办法“概括”这一点，从而拥有这样的“最终”代码：uint16(200).write(writer, encoding)uint64(len(myArray)).write(writer, encoding)[]byte(time.Now().Format("2006-01-02T15:04:05-0700")).write(writer, encoding)（也许这是不可能的，我只是想知道我是否必须在每次必须编写一些东西时复制/粘贴我的代码writer())

Answer 1

使用函数来避免复制/粘贴类似的代码：

func write(writer io.Writer, encoding binary.ByteOrder, value interface{}) {

    buf := new(bytes.Buffer)

    err := binary.Write(buf, encoding, value)

    if err != nil {

        panic(fmt.Sprint("binary.Write failed:", err))

    }

    _, _ = writer.Write(buf.Bytes())

}

这样称呼它：

write(writer, encoding, uint16(200))

因为字节。不需要缓冲区，写入功能可以简化为：

func write(writer io.Writer, encoding binary.ByteOrder, value interface{}) {

    err := binary.Write(writer, encoding, value)

    if err != nil {

        panic(fmt.Sprint("binary.Write failed:", err))

    }

}

此版本的函数更改了错误的处理方式。问题中的代码忽略从 返回的错误。当从编写器返回错误时，此版本将死机。写。writer.Write

如果要比惊慌失措更优雅地处理错误，请调用 binary。直接写入：

err := binary.Write(writer, encoding, value)

if err != nil {

    // handle error

}

在此代码段中，可以是 、 等。valueuint16(200)uint64(len(myArray))