PHPUnit 模拟函数调用

Question

我希望测试的对象中有以下函数public function getUser($credentials, UserProviderInterface $userProvider){    $resourceOwner = $this->getAuthClient()->fetchUserFromToken($credentials);    // ... Code to create user if non-existent, update values, etc.    // ... Basically the code I want to test is here    return $user;}该getAuthClient()调用返回一个Client具有可用功能的对象fetchUserFromToken我怎样才能在 PHPUnit 测试中模拟fetchUserFromToken返回一个ResourceOwner对象？因为实际函数做了很多认证机制，超出了本测试用例的范围

Answer 1

我找到了一个名为Runkit的 php 库，但这不是我想要细读的方法。对于手头的问题，感觉很老套和矫枉过正。

函数getAuthClient()定义如下

private function getAuthClient() {

   return $this->clients->getClient('auth');

}

由$this->clients构造函数定义

public function __construct(ClientRepo $clients) {

    $this->clients = $clients;

}

因此，我模拟ClientRepo并公开了getClient()返回 Mock 的方法AuthClient（无论输入如何），以便我可以控制fetchUserFromToken()调用的返回。

public function testGetUser() {

    $client = $this->createMock(WebdevClient::class);

    $client->expects($this->any())

        ->method('fetchUserFromToken')

        ->will($this->returnCallback(function()

        {

            // TARGET CODE

        }));

    $clients = $this->createMock(ClientRegistry::class);

    $clients->expects($this->any())

        ->method('getClient')

        ->will($this->returnCallback(function() use ($client)

        {

            return $client;

        }));

    $object = new TargetObject($clients);

    $result = $object->getUser(...);

    // ... Assertions to follow

}