在 JBoss 上启动 Spring webapp 问题

Question

当我尝试部署我的项目时，这会出现 bean 的问题，我无法解决它，我附上了错误和生成它的类。我需要帮助来解决这个问题。我提前谢谢你。应用程序无法启动描述：co.com.coomeva.golden.service.ws.main.GreetingController 中的字段发件人需要找不到类型为“co.com.coomeva.golden.service.ws.jms.DistributorSender”的 bean。注入点有以下注解：- @org.springframework.beans.factory.annotation.Autowired(required=true) 行动：考虑定义一个 'co.com.coomeva.golden.service.ws.jms.DistributorSender 类型的 bean ' 在您的配置中。22:41:15,280 错误 [org.jboss.msc.service.fail] (ServerService 线程池 -- 69) MSC000001: 无法启动服务 jboss.undertow.deployment.default-server.default-host./Golden: org. jboss.msc.service.StartException 在服务 jboss.undertow.deployment.default-server.default-host./Golden: java.lang.RuntimeException: org.springframework.beans.factory.UnsatisfiedDependencyException: 创建名称为“greetingController”的 bean 时出错：通过字段“sender”表示的依赖关系不满足；嵌套异常是 org.springframework.beans.factory.NoSuchBeanDefinitionException：没有“co.com.coomeva.golden.service.ws.jms.DistributorSender”类型的合格 bean 可用：预计至少有 1 个有资格作为自动装配候选者的 bean。依赖注释：{@org.springframework.beans.factory.annotation.Autowired(required=true)} at org.wildfly.extension.undertow.deployment.UndertowDeploymentService$1.run(UndertowDeploymentService.java:84) at java.util.concurrent 

Answer 1

我转载了你的问题。以下是您需要进行的更改：

1. @SpringBootApplication(scanBasePackages ={"co.com.coomeva.golden.service.ws.jms","co.com.coomeva.golden.service.ws.main"})

2. 您需要使用或DistributorSender之类的注释使您的班级具有弹簧意识。@Component@Repository

GoldenServiceApplication.java

@SpringBootApplication(scanBasePackages = {"co.com.coomeva.golden.service.ws.jms","co.com.coomeva.golden.service.ws.main"})

public class GoldenServiceApplication extends SpringBootServletInitializer 

{

public static void main(String[] args) {

    SpringApplication.run(applicationClass, args);

}

@Override

protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {

    return application.sources(applicationClass);

}

private static Class<GoldenServiceApplication> applicationClass = 

GoldenServiceApplication.class;

}

@RestController

class GreetingController {

@Autowired

private DistributorSender sender;

@PostMapping("/distributor/records")

public GoldenResponse setGoldenRecord(@RequestBody String goldenRecord) 

{

    GoldenResponse response = new GoldenResponse();

    try {

        sender.publishMessage(goldenRecord);

        response.setCode(HttpStatus.OK.value());

        response.setMessage("Golden Record Published");

    } catch (Exception e) {

        String error = e.getCause().toString();

        error = error.length() > 200 ? error.substring(0, 200) : error;

        response.setMessage("Golden Record was not published. Error:" + error);

    }

    return response;

}

@RequestMapping("/hello/{name}")

String hello(@PathVariable String name) {

    return "Hello, " + name + "!";

}

@GetMapping("/Example2")

public GoldenResponse exampleDist() {

    GoldenResponse goldenResponse = new GoldenResponse();

    goldenResponse.setCode(1);

    goldenResponse.setMessage("sd");

    System.out.println("Vinagre");

    return goldenResponse;

    }

}

和 DistributorSender.java

package co.com.coomeva.golden.service.ws.jms;

import org.springframework.stereotype.Component;

@Component

public class DistributorSender {

private String record;

public void publishMessage(String record) {

    this.record = record;

}

}

Answer 2

请删除不必要的注释@ComponentScan，@Configuration和@EnableAutoConfiguration

在您有任何特定要求之前，只有下面给定的代码足以运行您的应用程序。

@SpringBootApplication

public class GoldenServiceApplication extends SpringBootServletInitializer {

    public static void main(String[] args) {

        SpringApplication.run(applicationClass, args);

    }

    @Override

    protected SpringApplicationBuilder configure(SpringApplicationBuilder application) {

        return application.sources(applicationClass);

    }

    private static Class<GoldenServiceApplication> applicationClass = GoldenServiceApplication.class;

}

Answer 3

Spring-boot 应用程序的一个好习惯：

将您的 Application 类（具有@SpringBootApplication注释的类）存储在主包中，并将所有其他*.java文件放在该包下，以便 Spring Application 可以找到它们。