.Net Core 2.1 中的寻呼机

Question

我从 NuGet Link添加了 ReflectionIT.Mvc.Paging但我遇到了问题。在控制器中，我有 2 种方法，索引和组织。当我在 Orginizations 视图中并按下控制器中编号为“2”的页面时，将转到索引而不是 Organizations 方法。如何强制它继续我想要的方法或扩展它 @await this.Component.InvokeAsync("Pager", new { pagingList = this.Model })以将方法名称作为参数传递？控制器：   public IActionResult Index()        {            return View();        }     public async Task<IActionResult> Organizations(int page=1)        {            var userlist = _context.Users.Include(u => u.UserRoles).ThenInclude(u => u.Role).Where(o => o.UserRoles.All(r => r.Role.Name == "Company") && o.IsActive == true).AsNoTracking().OrderByDescending(o => o.Company);            var model = await PagingList.CreateAsync(userlist, 2, page);            return View(model);        }看法：@model ReflectionIT.Mvc.Paging.PagingList<CharityProject.Models.ApplicationUser>@using ReflectionIT.Mvc.Paging@addTagHelper *, ReflectionIT.Mvc.Paging@{    ViewData["Title"] = "Organizations";    Layout = "~/Views/Shared/_Layout.cshtml";}<div class="container py-lg-5 py-md-5 py-sm-4 py-4">    <h2 class="pageTitles">Organizations</h2>    <div class="row">        <nav aria-label="NewsFeed navigation example">            @await this.Component.InvokeAsync("Pager", new { pagingList = this.Model })        </nav>        <br />

Answer 1

您可以将 Action 属性设置为 PagingList 对象：

var model = await PagingList.CreateAsync(userlist, 2, page);
model.Action = "Organizations";