Javascript按与数字的最短距离对数组进行排序

Question

我需要以最接近数字的元素应该首先出现的方式对数组元素进行排序，而最远的元素应该排在最后。例如，let arr = [1,16,14,13,6,7,4,5,3,2,19,20,10,4,6]let number = 10resultArray should be [10, 13, 7, 14, 6, 6, 5, 16,4, 4, 3, 2, 19, 1, 20];提前致谢。

Answer 1

按到 的距离排序number，其中距离是两个数字之间的绝对差：

let arr = [1,16,14,13,6,7,4,5,3,2,19,20,10,4,6]

let number = 10

const distance = (a, t) => Math.abs(t - a);

arr.sort((a, b) => distance(a, number) - distance(b, number));

console.log(arr);

Answer 2

只需.sort()使用Math.abs.

let arr = [1, 16, 14, 13, 6, 7, 4, 5, 3, 2, 19, 20, 10, 4, 6]

let number = 10

let sortByShortestDistance = (arr, number) => arr.sort((a, b) => Math.abs(a - number) - Math.abs(b - number))

console.log(sortByShortestDistance(arr, number))