正则表达式匹配直到Java中的文本结尾

Question

我想使用正则表达式获取 From 字段的所有电子邮件地址，例如获取所有以“From：”开头并以“/n”新行结尾的文本行。这是我要应用此正则表达式的完整文本，Sent: Tue Mar 05 15:42:11 IST 2019From: [e-mail]: [e-mail]: Re: Foausrnisfseur invadlide (030000000000:3143)Message: ----------------------------Sent: Tue Mar 05 15:40:51 IST 2019From: [e-mail]: [e-mail]: Foausrnisfseur invadlide (O4562000888885456:3143)Message:This is not right please correctTermes de paiement Foausrnisfseur non spécifiésimpact potentiel: 3 000,00You should write From field with [e-mail] not From: field with [e-mail] in the columnDate détecté: 2019-02-26 12:55:03---- Please do not delete or modify this line. (2423000000000149:3143) -----------------------------Sent: Tue Mar 05 15:40:51 IST 2019From: [e-mail]: [e-mail]: Foausrnisfseur invadlide (O4562000888885456:3143)我尝试了以下模式，但没有奏效，[^.?!]*(?<=[.?\s!])string(?:(?=[\s.?!])[^.?!]*(?:[.?!].*)?)?$    /^([\w\s\.]*)string([\w\s\.]*)$/    "^\\w*\\s*((?m)Name.*$)"上述文本预期的预期结果是：[e-mail], [e-mail], [e-mail],PS。我想要 Java 逻辑的正则表达式

Answer 1

针对您的情况使用此正则表达式：

From:\s+([\w-]+@([\w-]+\.)+[\w-]+)

我已经用https://www.freeformatter.com/java-regex-tester.html#ad-output尝试了这个正则表达式，它符合您的要求。

您需要的比赛在捕获组 1 中。

工作演示：https ://regex101.com/r/dGaPbD/4

Answer 2

   String emailRegex = "[^\\s]+"; // Replace with a better one

    Matcher m = Pattern.compile("(?m)^From:\\s*(" + emailRegex + ")\\s*$").matcher(yourString);

    List<String> allMatches = new ArrayList<String>();

    while(m.find())

      System.out.println(m.group(1));

Answer 3

  String test = "   Sent: Tue Mar 05 15:42:11 IST 2019  "

            + "   From: [e-mail]  "

            + "   To: [e-mail]  "

            + "   Subject: Re: Foausrnisfseur invadlide (030000000000:3143)  "

            + "   Message:   "

            + "     "

            + "     "

            + "   ----------------------------  "

            + "     "

            + "   Sent: Tue Mar 05 15:40:51 IST 2019  "

            + "   From: [e-mail]  "

            + "   To: [e-mail]  "

            + "   Subject: Foausrnisfseur invadlide (O4562000888885456:3143)  "

            + "   Message:  "

            + "   This is not right please correct  "

            + "   Termes de paiement Foausrnisfseur non spécifiés  "

            + "   impact potentiel: 3 000,00  "

            + "   You should write From field with [e-mail]  "

            + "   and not From: field with [e-mail] in the column  "

            + "   Date détecté: 2019-02-26 12:55:03  "

            + "     "

            + "     "

            + "   ---- Please do not delete or modify this line. (2423000000000149:3143) ----  "

            + "     " + "   -------------------------  "

            + "   Sent: Tue Mar 05 15:40:51 IST 2019  " + "   From: [e-mail]  "

            + "   To: [e-mail]  "

            + "  Subject: Foausrnisfseur invadlide (O4562000888885456:3143)  ";

      String emailRegex = "[a-zA-Z0-9._%+-]+@[A-Za-z0-9.-]+\\.[a-zA-Z]{2,6}";

    Pattern pattern = Pattern.compile("From\\:\\s(" + emailRegex + ")");// From\\:\\s same as Form : and () here i added Email Id  regex or you also change to (.*\n) but not recommended

    Matcher match = pattern.matcher(test);

    while (match.find()) {

        System.out.println(match.group(1));

    }

输出 ：

 [e-mail]

[e-mail]

[e-mail]

Answer 4

试试这个模式：^From:\s*(\S+)$

它首先用 匹配行首^，然后匹配From:字面意思，然后用 匹配 0 个或多个空格\s*，然后匹配一个或多个非空格并将其存储在捕获组中，$匹配行尾。

要获取电子邮件地址，只需使用第一个捕获组的值。

演示