输入是一个int，变量是一个字符串，如果字符串大于if语句中的int

Question

input是一个int，变量是一个字符串，如果字符串大于if语句中的int，我想要一个动作。我正在使用 python 3.8name = input ("What is your name?")print(name)# print ("Yes or No")age= input ("how old are you?")if age >= 50:    print (name, "You are looking good for your age!")else:    print(name, "You are getting old.")print("Peace Out")

Answer 1

将age字符串转换为 int，然后签入 if 语句。

age = int(input('How old are you?'))

Answer 2

您可以在获取用户输入时使用将age变量转换为 an 。intint()

name = input ("What is your name?")

print(name)

# make the input an int

age= int(input("how old are you?"))

if age >= 50:

    print (name, "You are looking good for your age!")

else:

    print(name, "You are getting old.")

print("Peace Out")

Answer 3

您需要将输入转换为 int。输入将其作为字符串接收，然后您需要将其转换为 int 以便能够将苹果与苹果进行比较

age = int(input("How old are you?"))

在 python 3.8 中，您还可以使用海象运算符 (:= )。您的代码将如下所示：

# Assign the value from input and print in 1 line thanks to :=    

print(name := input("What is your name?"))

# Make age an int and assign the value in your if statement with the walrus operator

if age := int(input("how old are you?")) >= 50:

    print (name, " You are looking good for your age!")

else:

    print(name, " You are getting old.")

print("Peace Out")

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