写了一小段，错误太多，没信心了，谁能帮帮我！

Question

#include<iostream>using namespace std;class Matrix{float* a;int m,n;public:Matrix(float* s,int y,int z){this->a = a;m = y;n = z;a = new float [m][n];for(int i = 0 ; i<m; i++)for(int j = 0 ; j<n ; j++)a[i][j] = s[i][j];}~Matrix{for(int i = 0 ; i<m ; i++)delete []p[i];}Matrix& operator=(Matrix& d){for(int i = 0 ; i<m; i++)for(int j = 0 ; j<n ; j++)*(a+i)+j = d.a[i][j];return *this;}};void Input(float* s,int m,int n){for(int i = 0 ; i<m ; i++)for(int j = 0; j<n ; j++)cin>>a[i][j];}int main(){int m,n;cout<<"请输入矩阵的行数及列数:";cin>>m>>n;float s[m][n],d[m][n];Input(s,m,n);Input(d,m,n);Matrix a(s,m,n);Matrix b(d,m,n);Matrix c(s,m,n);b = a;c = a + b;c = a - b;return 0;}

Answer 1

用一维数组通过下标映射来实现二维数组要简单些。
例如，假设a为一个具有m*n个元素的一维数组，则*(a+i*n+j)可以看成是具有m行n列的二维数组的第m行第n列的元素。
下面是完整程序：
#include<iostream>
using namespace std;

class Matrix{
float* a;
int m,n;
public:
Matrix(float* s=0,int y=0,int z=0)
{
//this->a = a;
m = y;
n = z;
if(m==0 || n==0)
a=0;
else{
a = new float[m*n]; //[m][n];
for(int i = 0 ; i<m; i++)
for(int j = 0 ; j<n ; j++)
*(a+i*n+j)=*(s+i*n+j); //a[i][j] = s[i][j];
}
}
Matrix(Matrix& s){ //拷贝构造函数
m=s.m;
n=s.n;
a = new float[m*n]; //[m][n];
for(int i = 0 ; i<m; i++)
for(int j = 0 ; j<n ; j++)
*(a+i*n+j) = *(s.a+i*n+j);
}
~Matrix() //()
{
// for(int i = 0 ; i<m ; i++)
delete[] a; //p[i];
}
Matrix& operator=(Matrix& d)
{
if(&d==this)
return *this;
if(a!=0)
delete[] a;
m=d.m;
n=d.n;
a = new float[d.m*d.n];
for(int i = 0 ; i<m; i++)
for(int j = 0 ; j<n ; j++)
*(a+i*n+j)=*(d.a+i*n+j); //*(a+i)+j = d.a[i][j];
return *this;
}
Matrix operator+(Matrix& d)
{
Matrix temp(a,m,n);
for(int i = 0 ; i<m; i++)
for(int j = 0 ; j<n ; j++)
*(temp.a+i*n+j) =*(a+i*n+j) + *(d.a+i*n+j);
return temp;
}

Matrix operator-(Matrix& d)
{
Matrix temp(a, m, n);
for(int i = 0 ; i<m; i++)
for(int j = 0 ; j<n ; j++)
*(temp.a+i*n+j) -= *(d.a+i*n+j);
return temp;
}
void display(){
if(m==0 || n==0){
cout <<"该矩阵没有元素\n";
return;
}
for(int i = 0 ; i<m; i++){
for(int j = 0 ; j<n ; j++)
cout <<*(a+i*n+j) <<" ";
cout <<endl;
}
}
};

void Input(float* s,int m,int n)
{
cout<<"请输入" <<m <<"*" <<n <<"矩阵:";
for(int i = 0 ; i<m ; i++)
for(int j = 0; j<n ; j++)
cin>> *(s+i*n+j); //a[i][j];
}

int main()
{

int m,n;
cout<<"请输入矩阵的行数及列数:";
cin>>m>>n;
float *s, *d; //s[m][n],d[m][n];
s=new float[m*n];
d=new float[m*n];
Input(s,m,n);
Input(d,m,n);
Matrix a(s,m,n);
Matrix b;
Matrix c(s,m,n);
cout <<"Matrix a:\n";
a.display();
cout <<"Matrix b:\n";
b.display();
cout <<"Matrix c:\n";
c.display();

b = a;
cout <<"Matrix b (=a):\n";
b.display();
c = a + b;
cout <<"Matrix c (=a+b):\n";
c.display();
c = a - b;
cout <<"Matrix c (=a-b):\n";
c.display();

delete[] s;
delete[] d;
return 0;
}