PHP Json 文件合并

Question

我需要将 json 文件合并到 1 个文件中。我在 3 个文件中有这样的 json{    "count": 2077,    "records": [{        "comm_date": "51529",        "Certificate_Number": "31",},{        "comm_date": "51529",        "Certificate_Number": "31",}]} 但是探针是因为我有计数和记录数组在这里所以它没有成功合并<?php$a1 = file_get_contents ("EngroClaims.json");$a2 = file_get_contents ("EngroClaims2.json");$a6 = file_get_contents ("SCB1Claims.json");$a7 = file_get_contents ("TotalParcoClaims.json");$a8 = file_get_contents ("SAPTClaims.json"); $r = array_merge(json_decode($a1,true), json_decode($a2,true), json_decode($a6,true), json_decode($a7,true), json_decode($a8,true));file_put_contents('conventional.json', json_encode($r));?>这是我的 php 代码，它工作正常。但我需要合并所有数组records例子第一个文件{    "count": 2,    "records": [{        "comm_date": "1",},{        "comm_date": "2",}]} 第二个文件{    "count": 3,    "records": [{        "comm_date": "1",},{        "comm_date": "2",},{        "comm_date": "3",}]} 预期结果{    "count": 9, //this count value is not imprtant assume it will show 1    "records": [{        "comm_date": "1",},{        "comm_date": "2",},{        "comm_date": "1",},{        "comm_date": "2",},{        "comm_date": "3",}]} 

Answer 1

您可以使用这种方式；

<?php

$a1 = file_get_contents ("EngroClaims.json");

$a2 = file_get_contents ("EngroClaims2.json");

$a1 = json_decode($a1, true);

$a2 = json_decode($a2, true);

$count = $a1["count"] + $a2["count"];

$data = array();

$data["count"] = $count;

foreach ($a1["records"] as $row) {

    $data["records"][] = $row;

}

foreach ($a2["records"] as $row) {

    $data["records"][] = $row;

}

echo json_encode($data);

我发现了你的问题。去掉 json 中的逗号（代码中有解释）。

$a1 = '{

    "count": 2077,

    "records": [

{

        "comm_date": "51529",

        "Certificate_Number": "31", <--- THIS IS A PROBLEM

},

{

        "comm_date": "51529",

        "Certificate_Number": "31", <--- THIS IS A PROBLEM

}

]}';

/* in order for this solution to work you need to delete that comma. 

    Because there isn't a following data in the json so the comma should not be there */

检查此链接； http://sandbox.onlinephpfunctions.com/code/8dfab10352cf4966c95eb599d2ed8644b24b49ab

Answer 2

如果不需要计数，可以使用 array_merge_recursive

$r = array_merge_recursive(json_decode($a1,true), json_decode($a2,true),json_decode($a3,true));
echo json_encode($r);

会给你结果

{"count":[3,3,3],"records":[{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"},{"comm_date":"1"},{"comm_date":"2"},{"comm_date":"3"}]}