按下设备上的后退按钮时,如何防止应用程序最小化/退出?在我的设备上按下返回按钮时,我试图分配“浏览器返回”功能,这是我的代码:import 'react-native-get-random-values';import React, { useState, useRef, Component, useEffect } from 'react'import { Alert, SafeAreaView, StyleSheet, StatusBar, View, Text, ScrollView, BackHandler, RefreshControl} from 'react-native'import WebView from 'react-native-webview'import Icon from 'react-native-vector-icons/FontAwesome';import { Button } from 'react-native-elements';const App = () => { function backButtonHandler(){} function refreshHandler(){ if (webviewRef.current) webviewRef.current.reload() } useEffect(() => { BackHandler.addEventListener("hardwareBackPress", backButtonHandler); return () => { BackHandler.removeEventListener("hardwareBackPress", backButtonHandler); }; }, [backButtonHandler]); let jscode = `window.onscroll=function(){window.ReactNativeWebView.postMessage(document.documentElement.scrollTop||document.body.scrollTop)}`; const [canGoBack, setCanGoBack] = useState(false) const [currentUrl, setCurrentUrl] = useState('') const [refreshing, setRefreshing] = useState(false); const [scrollviewState, setEnableRefresh] = useState(false); const webviewRef = useRef(null) const scrollviewRef = useRef(false) backButtonHandler = () => { if (webviewRef.current) webviewRef.current.goBack() }我的问题是当我按下设备上的后退按钮时,它确实调用了backButtonHandler函数并且我的 webview 导航回来,但同时应用程序也最小化了..有没有办法防止这种情况?
1 回答

慕斯709654
TA贡献1840条经验 获得超5个赞
将您的 backButtonHandler 方法更改为仅返回 true,当您的 backHandler 方法返回 true 时,它实际上什么也不做 onPress Back button :
backButtonHandler = () => {
return true;
}
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