从标签python的onclick属性获取URL

Question

我正在尝试使用 selenium python 访问标签的 onclick 属性中存在的 URL。它存在于 javascript 函数中。我已经尝试了各种技术来做到这一点，但我还没有找到解决方案。我尝试使用 execute_script 方法执行单击功能。我也尝试过 get_attribute 来获取 onclick 函数，但它没有返回。我想访问 openPopUpFullScreen 函数中的 url这是html：<td class="tdAction"><div class="formResponseBtn icon-only"><a href="#fh" onclick="javascript: openPopUpFullScreen('/esop/toolkit/negotiation/rfq/publicRfqSummaryReport.do?rfqId=rfq_229969', '');" class="openNewPage" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions"><img src="/esop_custom/images/buttons/print_button.png" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions" alt="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions"><img src="/esop_custom/images/buttons/openNewWindow_button.png" title="(Opens in new window)" alt="(Opens in new window)"></a></div></td>这是python代码：url=browser.find_element_by_xpath("//img[@title='Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions']").click()print(browser.current_url)#it returns the previous page I am at.这是另一个：id=browser.find_element_by_css_selector(".openNewPage").get_attribute("onclick")print(id)#it returns none我需要 openPopUpFullScreen 函数中存在的 URL，但我无法弄清楚完成此操作的正确解决方案是什么。更新：我也尝试使用 beautifulsoup 来提取 onclick 函数，但它似乎没有出现：这是我的代码：content = browser.page_source.encode('utf-8').strip()soup = BeautifulSoup(content,"html.parser")res = soup.find("a",{"class":"openNewPage"})print(res)#it returns the complete tag but it does not contain onclick attribute#i tried using thisres = soup.find("a",{"class":"openNewPage"})[onclick]#it returns an error NameError: name 'onclick' is not defined

Answer 1

以下

from bs4 import BeautifulSoup

html = '''<td class="tdAction">

<div class="formResponseBtn icon-only">

<a href="#fh" onclick="javascript: openPopUpFullScreen('/esop/toolkit/negotiation/rfq/publicRfqSummaryReport.do?rfqId=rfq_229969', '');" class="openNewPage" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions">

<img src="/esop_custom/images/buttons/print_button.png" title="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions" alt="Open a new window to view > View or download a Summary of this PQQ/ITT which includes details of the PQQ/ITT settings, format and questions"><img src="/esop_custom/images/buttons/openNewWindow_button.png" title="(Opens in new window)" alt="(Opens in new window)">

</a>

</div>

</td>'''

soup = BeautifulSoup(html, features="lxml")

a = soup.find('a')

onclick = a.attrs['onclick']

left = onclick.find("'")

right = onclick.find("'",left+1)

print('URL is: {}'.format(onclick[left+1:right]))

输出

URL is: /esop/toolkit/negotiation/rfq/publicRfqSummaryReport.do?rfqId=rfq_229969

Answer 2

对于 get_attribute：

我认为您在没有“onclick”属性的情况下得到了错误的元素。

您应该扩展 css 选择器并确认它只会找到一个元素。

对于 current_url：

您应该先切换到新窗口。尝试使用以下代码：

# window_handles[-1] refer to last window created.

browser.switch_to.window(browser.window_handles[-1])

print(browser.current_url)