如何将我的“拆分”代码转换为正则表达式

Question

我有一个raw.txt在下面。ok: [192.168.1.1] => {    "OS": "Ubuntu(Core) "}ok: [192.168.1.2] => {    "OS": "Ubuntu (Core) "  }ok: [192.168.1.3] => {    "OS": "CentOS (Core) "}ok: [192.168.1.3] => {    "OS":"CentOS (Core) "  }ok: [192.168.1.5] => {    "OS": "Red Hat(Core) "}ok: [192.168.1.6] => {    "OS": "CentOS (Core) "  }我的 Python 代码如下所示如何转换为可取的输出f = open(r'raw.txt', 'r')s = f.read()list1 = s.split('\n')ip_list = []os_list = []for i in list1[::3]:    ip_list.append(i)for i in list1[1::3]:    os_list.append(i)y = [z[10:25] for z in os_list]os_l = [x.strip(' ').replace('"','').replace(' ','') for x in y]ip_l = [z[5:18] for z in ip_list]ip_l_rep = [x.strip(' ').replace(']','') for x in ip_l]{ip_l_rep[n]:os_l[n] for n in range(len(os_l))}我的输出和预期低于{'192.168.1.1': 'Ubuntu(Core)', '192.168.1.2': 'Ubuntu(Core)', '192.168.1.3': 'CentOS(Core)', '192.168.1.5': 'RedHat(Core)', '192.168.1.6': 'CentOS(Core)'}由于在这个程序中使用了多个操作，我决定在正则表达式的帮助下编写。我写了一些伪代码但没有成功。喜欢提取\d{1,3}.\d{1,3}.\d{1,3}.\d{1,3}.我的代码的任何增强也很感激

Answer 1

您可以使用正则表达式来捕获介于之间[]和之后的内容"OS": "：

import re

input = """

ok: [192.168.1.1] => {

    "OS": "Ubuntu(Core) "

}

ok: [192.168.1.2] => {

    "OS": "Ubuntu (Core) "

}

ok: [192.168.1.3] => {

    "OS": "CentOS (Core) "

}

ok: [192.168.1.3] => {

    "OS":"CentOS (Core) "

}

ok: [192.168.1.5] => {

    "OS": "Red Hat(Core) "

}

ok: [192.168.1.6] => {

    "OS": "CentOS (Core) "

}

"""

items = re.findall(r'\[(.*?)\].*?"OS": "(.*?)"', input, flags=re.S)

data = dict(items)  # only works as you have 2 items (IP, OSTYPE)

print(data)

# output: {'192.168.1.1': 'Ubuntu(Core) ', '192.168.1.2': 'Ubuntu (Core) ', '192.168.1.3': 'Red Hat(Core) ', '192.168.1.6': 'CentOS (Core) '}

Answer 2

这会从引号之间的文本中去除不需要的空间"：

import re

f = open(r'raw.txt', 'r')

text = f.read()

f.close()

pattern = r'\[(.+?)\].+?:\s*"\s*(.+?)\s*"'

result = dict(re.findall(pattern, text, flags=re.DOTALL))

print(result)

# {'192.168.1.1': 'Ubuntu(Core)', '192.168.1.2': 'Ubuntu (Core)', '192.168.1.3': 'CentOS (Core)', '192.168.1.5': 'Red Hat(Core)', '192.168.1.6': 'CentOS (Core)'}