将此作为维度数组

Question

我在制作维度数组时遇到问题，请帮助我使用 php，这是我的场景$arrayname = array["john","mell","ben","henz","len"];$arrayage = array["10","15","58","12","13"];$arraygender = array["male","female","male","male","female"]; 我想让它像$arrayidentify = array['name' => 'john', 'age' => '10', 'gender' => 'male'];等等，请帮忙 非常感谢

Answer 1

    class Person { 

        public $name = "pname";

        public $age = "21";

        public $gender = "MaleOrFemale";

        function __construct($name,$age,$gender){

        $this->name = $name;

        $this->age = $age;

        $this->gender = $gender;

    }

}

您可以使用 OOP 方法并创建一个对象来存储一个人的数据并创建一个人员数组

例子

$steve = new Person("Steve Jobs","60","Male"); 

这将创建一个名为 steve 的人对象 $steve ，年龄 60 ，性别 Male

您可以根据需要创建可能的人对象并将其放在数组中

$jeff = new Person("Jeff Bezos","50","Male");

$bill = new Person("Bill Gates","64","Male");

将以上所有内容放在一个数组中，如下所示

$persons = array($steve,$jeff,$bill);

尝试下面的代码自学并理解它我使用过对象和构造函数在 w3schools.com 中了解它们

<?php 

class Person { 

    public $name = "pname";

    public $age = "21";

    public $gender = "MaleOrFemale";

    function __construct($name,$age,$gender){

    $this->name = $name;

    $this->age = $age;

    $this->gender = $gender;

}

}

$steve = new Person("Steve Jobs","60","Male");

$jeff = new Person("Jeff Bezos","50","Male");

$bill = new Person("Bill Gates","64","Male");

$persons = array($steve,$jeff,$bill);

foreach($persons as $person){

    echo"Person Name : ".$person->name."<br>";

    echo"Person Age : ".$person->age."<br>";

    echo"Person Gender : ".$person->gender."<br><br>";

}

?>

Answer 2

一个简单的循环将在这里执行：

<?php

$names   = ["john","mell","ben","henz","len"];

$ages    = ["10","15","58","12","13"];

$genders = ["male","female","male","male","female"]; 

for($i=0, $c=count($names), $out=[]; $i<$c; $i++) {

    $out[] = [

        'name'   => $names[$i],

        'age'    => $ages[$i],

        'gender' => $genders[$i]

    ];

}

var_export($out);

输出：

array (

    0 => 

    array (

      'name' => 'john',

      'age' => '10',

      'gender' => 'male',

    ),

    1 => 

    array (

      'name' => 'mell',

      'age' => '15',

      'gender' => 'female',

    ),

    2 => 

    array (

      'name' => 'ben',

      'age' => '58',

      'gender' => 'male',

    ),

    3 => 

    array (

      'name' => 'henz',

      'age' => '12',

      'gender' => 'male',

    ),

    4 => 

    array (

      'name' => 'len',

      'age' => '13',

      'gender' => 'female',

    ),

  )

您可以将 for 循环换成 foreach：

foreach ($names as $k => $v) {

    $out[] = [

        'name'   => $names[$k],

        'age'    => $ages[$k],

        'gender' => $genders[$k]

    ];

}

Answer 3

我认为@ajay-kumar 提供的array_map 解决方案是最好的，我会提出一个更动态和更易于阅读的解决方案

function bindDatas(&$resultSolution, $inputData, $keyName) 

{

    foreach ($inputData as $key => $value) {

        $resultSolution[$key][$keyName] = $value;

    }

}

一些人认为的测试代码是这样的：

//your code here

bindDatas($resultSolution, $arrayname, 'name');

bindDatas($resultSolution, $arrayage, 'age');

bindDatas($resultSolution, $arraygender, 'gender');

echo '<pre>';

print_r($resultSolution);

echo '</pre>';

确实，$key 变量引用了 $inputData 中的位置，但我们在这里使用它是因为我们希望保持全局数组中的顺序