PHP如何在特殊字符之前获取字符串？

Question

我试图从这个字符串中获取：UPS EXPRESSS_SAVER - 1 天住院。部分：EXPRESSS_SAVER我尝试了以下代码：它从字符串的 4 个索引开始，在特殊字符“-”之前结束$shippingMethod = "UPS EXPRESSS_SAVER - 1 día hab.";$shippingServiceId = substr($shippingMethod, 4, strpos($shippingMethod,'-'));这让我回来了：EXPRESSS_SAVER - 1我也试过：$shippingServiceId = substr($shippingMethod, 4, strpos($shippingMethod,' '));但得到：EXP

Answer 1

您可以使用以下代码点获取 EXPRESSS_SAVER

$shippingMethod = "UPS EXPRESSS_SAVER - 1 día hab.";

$shippingMethodArr = explode(" ",$shippingMethod);

$shipped = $shippingMethodArr[1];

Answer 2

 $shippingMethod = "UPS EXPRESSS_SAVER - 1 día hab.";

 $position = 4;

 $shippingServiceId = substr($shippingMethod, $position, strpos($shippingMethod,'-') - $position);

 echo $shippingServiceId;