添加数组的连续元素

Question

尝试将数组的两个元素相加，即[2,4,6,8,10,12] 应该返回一个新数组 [6, 14, 22] (2+4, 6+8, 10+12)[4,2,7,15,35,23] 应该返回一个新数组 [6,22,58] - (4+2, 7+15, 35+23)新的、沮丧的并且无法正确地制定一个 for 循环来达到预期的结果。到目前为止我尝试过的错误解决方案： var newArray = [];  for (let i = 0; i<numbers.length - 1; i +=2) {    newArray = numbers.push(numbers[i] + numbers[i] + 1);    console.log(newArray);  }

Answer 1

你很接近：

let newArray = [];

const numbers = [2,4,6,8,10,12];

for (let i = 0; i < numbers.length - 1; i += 2) {

  newArray.push(numbers[i] + numbers[i + 1]);

}

console.log(newArray);

Answer 2

快速简单，假设输入总是一个偶数长度的数组

const data = [4,2,7,15,35,23]

const length = data.length

const res = []

for(let i = 0; i < length; i+=2){

  var num1 = data[i]

  var num2 = data[i + 1]

  res.push(num1 + num2)

}

console.log(res)