将列表分配给构造函数

Question

我正在编写一个 Hangman 游戏，为此我创建了下面的课程。其中一种方法是用*符号隐藏单词并显示猜测的字母。为此，我在方法中创建了一个列表，并在方法中def hide_word(self)调用它constructor以显示板上隐藏的单词print_game_status(self)。我想知道上面标记的行是有效的还是不好的做法。PS：部分线路未完成。# Classclass Hangman:    # Constructor    def __init__(self, word):        self.word = word        self.hidedWord = self.hide_word() # <-- This is valid or is a bad practice?    # Method to guess the letter    def guess(self, letter):        if letter in self.word:            correctLetters.append(letter)            self.hidedWord[1] = 'Y' # <-- This only a test, at first it works        else:            wrongLetters.append(letter)    # Method to check if game is over    # def hangman_over(self):    # Method to check if the player won    # def hangman_won(self):    # Method to hide the letter on the board    def hide_word(self):        return ['*' for x in self.word]    # Method to check the status game and print the board on the screen    def print_game_status(self):     print(board[0])     print(*self.hidedWord)     print('Wrong letters: ' + ', '.join(wrongLetters))     print('Correct letters: ' + ', '.join(correctLetters))# Function to read a word randomly from the word bankdef rand_word():    with open('palavras.txt', 'rt') as f:        bank = f.readlines()    return bank[random.randint(0, bank.index(max(bank)))].strip()# Main functiondef main():    # Object    game = Hangman(rand_word())    # While the game is not over, print the status, request a letter and read caracter    while(exit != True):        # Check the status game        game.print_game_status()        # Input from user        inputUser = input('Type a letter: ')        game.guess(inputUser)

Answer 1

由于您只处理单词，这意味着输入通常很短，因此hidedWord您constructor不需要self.hide_word().

但是，如果您正在处理较长的输入，例如长句子甚至文本，最好只调用self.hide_word()一次并有一个属性来保存其值，因为每次调用该函数都会减慢您的游戏速度。