从文本文件中计算特定单词的列表-Python

Question

我想计算特定单词的出现次数（连词：“also”、“although”、“and”、“as”、“because”、“before”、“but”、“for”、“if” , “nor”, “of”, “or”, “since”, “that”, “though”, “until”, “when”, “whenever”, “whereas”, “which”, “while”, “然而”）以及来自 txt 文件的标点符号这就是我所做的：def count(fname, words_list):if fname:    try:        file = open(str(fname), 'r')        full_text = file.readlines()        file.close()        count_result = dict()        for word in words_list:            for text in full_text:                if word in count_result:                    count_result[word] = count_result[word] + text.count(word)                else:                    count_result[word] = text.count(word)        return count_result    except:        print('Something really bad just happened!')print(count('sample2.txt', ["also", "although", "and", "as", "because", "before", "but", "for", "if", "nor", "of","or", "since", "that", "though", "until", "when", "whenever", "whereas","which", "while", "yet", ",", ";", "-", "'"]))但它的作用是将“是”计入“作为”，我该如何解决它或者有没有其他方法来归档它？谢谢预期输出类似于：{'also': 0, '虽然': 0, 'and': 27, 'as': 2, 'because': 0, 'before': 2, 'but': 4, 'for': 2, ' if': 2, 'nor': 0, 'of': 13, 'or': 2, 'since': 0, 'that': 10, 'though': 2, 'until': 0, 'when' : 3, 'whenever': 0, 'whereas': 0, 'which': 0, 'while': 0, 'yet': 0, ',': 41, ';': 3, '-': 1 , "'": 17, 'words_per_sentence': 25.4286, 'sentences_per_par': 1.75}

Answer 1

def word_count(fname, word_list):

    count_w = dict()

    for w in word_list:

        count_w[w] = 0

    with open(fname) as input_text:

        text = input_text.read()

        words = text.lower().split()

        for word in words:

            _word = word.strip('.,:-)()')

            if _word in count_w:

                count_w[_word] +=1

    return count_w

def punctaction_count(fname, punctaction):

    count_p = dict()

    for p in punctaction:

        count_p[p] = 0

    with open(fname) as input_text:

        for c in input_text.read():

            if c in punctaction:

                count_p[c] +=1

    return count_p

print(word_count('c_prog.txt', ["also", "although", "and", "as", "because", "before", "but", "for", "if", "nor", "of", "or", "since", "that",

                                "though", "until", "when", "whenever", "whereas", "which", "while", "yet"]))

print(punctaction_count('c_prog.txt', [",", ";", "-", "'"]))

如果您想在一个功能中执行此操作：

def word_count(fname, word_list, punctaction):

    count_w = dict()

    for w in word_list:

        count_w[w] = 0

    count_p = dict()

    for p in punctaction:

        count_p[p] = 0

    with open(fname) as input_text:

        text = input_text.read()

        words = text.lower().split()

        for word in words:

            _word = word.strip('.,:-)()')

            if _word in count_w:

                count_w[_word] +=1

        for c in text:

            if c in punctaction:

                count_p[c] +=1

    count_w.update(count_p)

    return count_w

print(word_count('c_prog.txt', ["also", "although", "and", "as", "because", "before", "but", "for", "if", "nor", "of", "or", "since", "that",

                                "though", "until", "when", "whenever", "whereas", "which", "while", "yet"], [",", ";", "-", "'"]))

Answer 2

在 2.7 和 3.1 中，您要实现的目标有特殊的Counter dict

由于您尚未发布任何示例输出。我想给你一个你可以使用的方法。维护一个列表。在列表中附加您需要的这些单词。例如，如果您接近单词“also”，请将其附加到列表中。

>>> l.append("also")

>>> l

['also']

同样，你遇到“虽然”这个词，列表变成：

>>> l.append("although")

>>> l

['also', 'although']

如果您再次遇到“也”，请再次将其附加到上面的列表中。

列表变为：

['also', 'although', 'also']

现在使用 Counter 来计算列表元素的出现次数：

>>> l = ['also', 'although', 'also']

>>> result = Counter(l)

>>> l

['also', 'although', 'also']

>>> result

Counter({'also': 2, 'although': 1})