访问函数内部定义的列表

Question

运行代码时，它会按计划要求输入，但未定义列表 alpha。首先输入没有读取，所以我更改了缩进，但是没有解决定义问题。def newclassification1(alpha,bravo):        alpha = ["Jacob", "Jane", "Jim"]        bravo = ["Male", "Female", "Unknown"]    name = input("What is the persons name?")    if name in alpha:        while True:            print(bravo[alpha.index(name)])    else:        print("The persons name is not in the register.")错误信息：Traceback（最近一次调用最后一次）：文件“”，第 7 行，在 NameError：名称 'alpha' 未定义

Answer 1

我不知道您的最终目的，但这两个代码在Python3上没有任何错误。

第一个：

def newclassification1(alpha,bravo):

    name = input("What is the persons name?")

    if name in alpha:

        while True:

            print(bravo[alpha.index(name)])

    else:

        print("The persons name is not in the register.")

newclassification1(["Jacob", "Jane", "Jim"], ["Male", "Female", "Unknown"])

第二个：

def newclassification1(alpha,bravo):

    alpha = ["Jacob", "Jane", "Jim"]

    bravo = ["Male", "Female", "Unknown"]

    name = input("What is the persons name?")

    if name in alpha:

        while True:

            print(bravo[alpha.index(name)])

    else:

        print("The persons name is not in the register.")

newclassification1([], [])

Answer 2

正如其他人所指出的，您应该修复缩进，并用您的论点找出一些东西。首先，当你在函数中定义alpha和bravo时，每次调用它们都会被重写，我想你不希望发生这种情况。其次，你应该修复缩进。我建议有以下几点：

def newclassification1(alpha=["Jacob", "Jane", "Jim"],bravo=["Male", "Female", "Unknown"]):

        name = input("What is the persons name?")

        if name in alpha:

            print(bravo[alpha.index(name)])

        else:

            print("The persons name is not in the register.")

这样，默认情况下，您将使用您的alpha=["Jacob", "Jane", "Jim"]，bravo=["Male", "Female", "Unknown"]但稍后在调用该函数时可以轻松地将其更改为您想要的任何内容。

此外，您不需要while True零件，因为它会在不停止执行的情况下运行

Answer 3

def newclassification1(name):

    alpha = ["Jacob", "Jane", "Jim"]

    bravo = ["Male", "Female", "Unknown"]

    if name in alpha:

        print(bravo[alpha.index(name)])

    else:

        print("The persons name is not in the register.")

name = input("What is the persons name?")

newclassification1(name)

Answer 4

我做了一些调整，主要是从函数中删除 alpha 和 bravo。

alpha = ["Jacob", "Jane", "Jim"]

bravo = ["Male", "Female", "Unknown"]

def newclassification1(alpha,bravo):

    name = input("What is the persons name?")

    if name in alpha:

        print(bravo[alpha.index(name)])

    else:

        print("The persons name is not in the register.")

newclassification1(alpha,bravo)

这是可行的，因为由于您将 alpha 和 bravo 传递给函数，因此这些变量应该在函数外部定义。我也把你while改成了一个if，否则你会得到无限的输出。我正在共享的功能的输出：

What is the persons name?Jim

Unknown

What is the persons name?Jane

Female

What is the persons name?a

The persons name is not in the register.

给定 OP 注释：alpha并且bravo 必须在函数中定义。

def newclassification1(alpha = [],bravo = []):

    alpha = ["Jacob", "Jane", "Jim"]

    bravo = ["Male", "Female", "Unknown"]

    name = input("What is the persons name?")

    if name in alpha:

        print(bravo[alpha.index(name)])

    else:

        print("The persons name is not in the register.")

newclassification1()

输出：

What is the persons name?Jim

Unknown

What is the persons name?Tim

The persons name is not in the register.

What is the persons name?Jane

Female