无法将列表转换为整数并遍历列表

Question

我正在努力弄清楚如何将列表转换为整数，并在每个元素上迭代一个函数。我希望该函数检查每个元素，并需要将列表中的每个元素转换为整数。years = ["25", "1955", "2000", "1581", "1321", "1285", "4365", "4", "1432", "3423", "9570"]def isLeap():    year = list(map(int, years))    if year in years >= 1583:        print(year, "Is a Gregorian Calendar Year.")    elif year in years < 1583:        print(year, "Is not a Gregorian Calendar Year.")    elif year in years % 400 == 0 or year in years % 4 == 0:        print(year, "Is a Leap Year.")    elif year in years % 400 == 1 or year in years % 4 == 1:        print(year, "Is NOT a Leap Year.")    else:        print("Test cannot be performed.")for i in years:    isLeap()

Answer 1

鉴于您正在尝试做的事情，我相信这是一种方法，将for您传递给函数的元素的循环（以列表格式）与if-elif-else您陈述的条件相结合。

years = ["25", "1955", "2000", "1581", "1321", "1285", "4365", "4", "1432", "3423", "9570"]

def isLeap(years):

    for i in years:

        if int(i) >= 1583:

            print(i, "Is a Gregorian Calendar Year.")

        elif int(i) < 1583:

            print(i, "Is not a Gregorian Calendar Year.")

        elif int(i) % 400 == 0 or int(years[i]) % 4 == 0:

            print(i, "Is a Leap Year.")

        elif int(i) % 400 == 1 or int(years[i]) % 4 == 1:

            print(i, "Is NOT a Leap Year.")

        else:

            print("Test cannot be performed.")

isLeap(years)

输出：

25 Is not a Gregorian Calendar Year.

1955 Is a Gregorian Calendar Year.

2000 Is a Gregorian Calendar Year.

1581 Is not a Gregorian Calendar Year.

1321 Is not a Gregorian Calendar Year.

1285 Is not a Gregorian Calendar Year.

4365 Is a Gregorian Calendar Year.

4 Is not a Gregorian Calendar Year.

1432 Is not a Gregorian Calendar Year.

3423 Is a Gregorian Calendar Year.

9570 Is a Gregorian Calendar Year.

Answer 2

您应该在isLeap函数之外进行从 string 到 int 的转换：

for year in map(int, years):

你的函数应该接受一个年份参数：

def isLeap(year)

你的测试应该是：if year >= 1583 # etc.

但是，这里还有一个逻辑问题：因为您使用的是if/elif，所以您永远无法确定某事是否是闰年，因为您的前两个 if 语句中的一个总是正确的。（它要么 >= 1583，要么 < 1583；不会检查其他条件。）

Answer 3

将字符串列表转换为整数列表可以通过列表推导简单地完成：

int_list = [int(year) for year in years]

代码中另一个明显的问题是理解变量的范围并将 args 传递给函数。

如果您迭代多年，则将年份项目传递给您的函数并在函数范围内使用

def isLeap(year):

...

for int_year in int_list:

    isLeap(int_year)