我收到一条错误消息，说“raw_input() 需要 1 到 2 个位置参数，但给出了 4 个”

Question

我正在尝试为一个简单的游戏编写代码。游戏的设计很好。但是我很难在原始输入函数中包含一个变量以及文本。任何帮助，将不胜感激。这是代码while True:    n=int(input("How many marbles to start with? ")) #Exercise 2.4    if (n>=1) and ((n%1)==0):        break    else:        print("enter a positive integer")while n>0:    p2=int(input("Player #1, there are",n, "marbles left. How many marbles will you take? "))    if (p2 not in (1,2,3)) or (p2>n):        print("not a proper input")    else:        n=n-p2        if n==0:            print("Player #1, you took the last marble and have won! ")           else:            while True:                p1=int(input("Player #2, there are",n, "marbles left. How many marbles will you take? "))                if (p1 not in (1,2,3)) or (p1>n):                    print("not a proper input")                else:                    n=n-p1                    if n==0:                        print("Player #2, you took the last marble and have won! ")                    break这是我收到的错误消息TypeError                                 Traceback (most recent call last)<ipython-input-13-d507a539ca61> in <module>      6         print("enter a positive integer")      7 while n>0:----> 8     p2=int(input("Player #1, there are",(n), "marbles left. How many marbles will you take? "))      9     if (p2 not in (1,2,3)) or (p2>n):     10         print("not a proper input")TypeError: raw_input() takes from 1 to 2 positional arguments but 4 were given

Answer 1

您需要将要传递的字符串连接input()成一个字符串，而不是像现在这样将它们作为单独的参数传递。代替：

input("Player #1, there are",(n), "marbles left. How many marbles will you take? ")

和

input("Player #1, there are " + str(n) + " marbles left. How many marbles will you take?")