无法移动 URL 以在 Django 中导入 URL

Question

django 2.2.5到目前为止，我在移动 url 时没有遇到问题。报告/reporting.html（索引）：...{% url "line_chart_json" %}...报告/views.pyclass LineChartJSONView(BaseLineChartView):    def get_labels(self):        """Return 7 labels for the x-axis."""        return ["January", "February", "March", "April", "May", "June", "July"]    ....当它在主应用程序 url.py 中时，很好from django.urls import path, includefrom reporting.views import LineChartJSONViewurlpatterns = [    ...    path('reporting/', include('reporting.urls')),    path('line_chart/json/', LineChartJSONView.as_view(),          name='line_chart_json'),]当我将其移至报告时from django.urls import pathfrom . import viewsfrom .views import LineChartJSONViewapp_name = 'reporting'urlpatterns = [    path('', views.summary_properties_user,         name='index'),    path('line_chart/json/', LineChartJSONView.as_view(),         name='line_chart_json'),]我在reporting.html上使用它时收到错误消息：NoReverseMatch at /reporting/Reverse for 'line_chart_json' not found. 'line_chart_json' is not a valid view function or pattern name.我假设一个简单的疏忽。仅仅几周后，Django URLs 仍然让我印象深刻。

Answer 1

它现在在报告应用程序中，因此您需要前缀：

{% url "reporting:line_chart_json" %}