在整个代码中初始化变量和/或更新值的小问题

Question

我之前有一个功能版本，它使用了较少的唯一变量和第一个变量的更多实例，但是在添加了两个与第一个变量相关的变量之后，我的代码出现了一个错误，表明我需要初始化我的变量“numbList”。理想情况下，我想在每个新行之后简单地更新“numbList”的值，然后更新“numbSquare”和“numbCube”的值。到目前为止，我还没有多少运气。public class Assignment2BPart2 {    public static void main(String[] args) {        int numbList;        int numbSquare;        int numbCube;        numbSquare = numbList * numbList;        numbCube = numbSquare * numbList;        System.out.println("The following is a table of values, showing numbers 0 - 10 and their squares and cubes.");        System.out.printf("%s%s%s%n", "Number   ", "Square  ", "Cube");        System.out.printf("%d \t %d \t %d%n", numbList = 0, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 1, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 2, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 3, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 4, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 5, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 6, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 7, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 8, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 9, numbSquare, numbCube);        System.out.printf("%d \t %d \t %d%n", numbList = 10, numbSquare, numbCube);           }}预期结果将是一个带有标题阅读的 3 列表数方立方第 1 列的其余部分是值 0-10，第 2 列是这些数字的平方，第 3 列是这些数字的立方。到目前为止，我无法在此迭代中运行代码。

Answer 1

实现这样重复的通常方法是使用for循环：

System.out.println("The following is a table of values, showing numbers 0 - 10 and their squares and cubes.");

System.out.printf("%s%s%s%n", "Number   ", "Square  ", "Cube");

for (int num = 0; num <= 10; num++) {

    System.out.printf("%d \t %d \t %d%n", num, num * num, num * num * num);

}

Answer 2

您正在寻找的解决方案是如何使代码和变量可重用。一种方法是使用函数，尽管您可能还没有学习到这一点。然后，您将使用 for 循环将数字 1 到 10 输入到您的函数中以获得所需的输出。

 public static int NumberSquared(int number)

 {

    return number*number;

 }

 public static int NumberCubed(int number)

 {

    return number*number*number;

 }

 public static void main(String[] args) 

 {

    for(int i=0; i <= 10; i++)

    {

        System.out.println("Number " + i + " Square: " + NumberSquared(i) + " Cube: " + NumberCubed(i));

    }

 }

Answer 3

逻辑是错误的，你必须在更新之后计算平方和立方体numbList，所以你必须使用任何循环或递归来做到这一点，但我更喜欢有两种方法返回 int 值，一个用于计算平方，另一个用于立方体

public class NewMain {

public static void main(String[] args) {

    int numbList = 0;

    System.out.println("The following is a table of values, showing numbers 0 - 10 and their squares and cubes.");

    System.out.printf("%s%s%s%n", "Number   ", "Square  ", "Cube");

    //

    System.out.printf("%d \t %d \t %d%n", numbList = 0, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 1, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 2, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 3, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 4, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 5, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 6, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 7, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 8, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 9, squareOfNumber(numbList), cubeOfNumber(numbList));

    System.out.printf("%d \t %d \t %d%n", numbList = 10, squareOfNumber(numbList), cubeOfNumber(numbList));

}

public static int squareOfNumber(int num) {

    return num*num;

}

public static int cubeOfNumber(int num) {

    return num*num*num;

  }

}

for循环你可以应用上面相同的逻辑

for(int i=0; i<=10; i++) {

        System.out.printf("%d \t %d \t %d%n", i, i*i, i*i*i);

    }

你也可以使用Math.pow()

nt intResult = (int) Math.pow(2, 3);

该方法将 2 提高到 3 的幂并返回结果