如下，请问如何编写!Y=1+3+5+7+...111？

Question

求解C语言编程用do while()语句编写!Y=1+3+5+7+...111

Answer 1

手写一下，未经调试
#include<stdio.h>
main()
{
int Y=0,i=1;
do
{
Y+=i;
i+=2;
}while(Y<=111);
printf("%d",Y);

}

Answer 2

int n=1;
int s=0;
do
{
s+=n;
n+=2;
}
while(n<=111)

Answer 3

main()
{
int i,sum=0;

do{
sum+=i;
i+=2
}while(i=1&&i<=111)

printf("%d",sum);
}